Question

The increase in the solubility of iodine in an aqueous solution of potassium iodide due to the formation of $K{{I}_{3}}$.
If the statement is true enter 1, else enter 0.

Answer 1

Hint: When potassium iodide is made to react with the iodine it results in the formation of compounds with the potassium iodide which is yellowish-brown in color and dissolves completely into it. Now answer the statement.

Complete answer:
By the term solubility, we mean the capacity of any substance to dissolve in the given solution i.e. the solute in the solution.
Now, let’s discuss iodine and potassium first. Iodine is a halogen and belongs to the p-block element and has the atomic number as 53 and mass number as 126. It is present in the 17th group and 5th period of the periodic table and in its outermost valence shell, it consists of seven electrons and has a strong tendency to gain one electron and attain the nearest noble gas configuration.
On the other hand, potassium is a alkali metal and belongs to the s-block element and has the atomic number as 19 and mass number as 39. It is present in the 1st group and 4th period of the periodic table and in its outermost valence shell, it consists of one electron and has a strong tendency to lose one electron and attain the nearest noble gas configuration.
Now considering the statement;
Potassium iodide when is made to react with the iodine, its solubility in it increases because iodine combines with the potassium iodide and results in the formation of potassium triiodide which is yellowish-brownish in colour. The reaction occur as;
$KI+{{I}_{2}}\to K{{I}_{3}}$
So, thus there is an increase in the solubility of iodine in an aqueous solution of potassium iodide due to the formation of $K{{I}_{3}}$.

Hence, this statement is true.

Note: The solubility of any substance is dependent on the properties of that very substance i.e. physical and the chemical properties and it also depends on the temperature and the pressure of the solution in which that is being dissolved.