
The graph of the hyperbolic tangent function for all real values is:
A. Strictly increasing
B. Strictly decreasing
C. Strictly increasing in the interval $\left[ {0,\infty } \right)$ and strictly decreasing in the interval $\left( { - \infty ,0} \right]$
D. Strictly increasing in the interval $\left( { - \infty ,0} \right]$ and Strictly decreasing in the interval $\left[ {0,\infty } \right)$
Answer
560.4k+ views
Hint:
We will write the value of $\tanh x$ as the ratio of hyperbolic sine function to hyperbolic cosine function. We will then draw a corresponding graph of the given function. Then, check the nature of the graph, that is where the graph is increasing or where the graph is decreasing.
Complete step by step solution:
The hyperbolic tangent function is the ratio of hyperbolic sine function to hyperbolic cosine function.
That is, $\tanh x = \dfrac{{\sinh x}}{{\cosh x}}$
Now, the value of $\sinh x = \dfrac{{{e^x} - {e^{ - x}}}}{2}$ and the value of $\cosh x = \dfrac{{{e^x} + {e^{ - x}}}}{2}$
Then, we can write the hyperbolic function of tangent as
$\tanh x = \dfrac{{\dfrac{{{e^x} - {e^{ - x}}}}{2}}}{{\dfrac{{{e^x} + {e^{ - x}}}}{2}}} = \dfrac{{{e^x} - {e^{ - x}}}}{{{e^x} + {e^{ - x}}}}$
We will plot the graph of $\tanh x$ to identify the nature of the function.
We can see that as the value of $x$ increases, then the value of $\tanh x$ also increases.
Therefore, the graph of the hyperbolic tangent function for all real values is strictly increasing.
Note:
The value of $\tanh x = \dfrac{{{e^x} - {e^{ - x}}}}{{{e^x} + {e^{ - x}}}}$. When $x$tends to infinity, $\tanh x$ tends to 1 such as
$
\mathop {\lim }\limits_{x \to \infty } \tanh x = \mathop {\lim }\limits_{x \to \infty } \dfrac{{{e^x} - {e^{ - x}}}}{{{e^x} + {e^{ - x}}}} \\
= \mathop {\lim }\limits_{x \to \infty } \dfrac{{\left( {1 - {e^{ - 2x}}} \right)}}{{\left( {1 + {e^{ - 2x}}} \right)}} \\
= \dfrac{{1 - \mathop {\lim }\limits_{x \to \infty } {e^{ - 2x}}}}{{1 + \mathop {\lim }\limits_{x \to \infty } {e^{ - 2x}}}} \\
= 1 \\
$
Similarly, when $x$ tends to $ - \infty $, the value of $\tanh x$ tends to $ - 1$. Then, we can say that the value becomes almost the same for higher or lower values of $x$.
We will write the value of $\tanh x$ as the ratio of hyperbolic sine function to hyperbolic cosine function. We will then draw a corresponding graph of the given function. Then, check the nature of the graph, that is where the graph is increasing or where the graph is decreasing.
Complete step by step solution:
The hyperbolic tangent function is the ratio of hyperbolic sine function to hyperbolic cosine function.
That is, $\tanh x = \dfrac{{\sinh x}}{{\cosh x}}$
Now, the value of $\sinh x = \dfrac{{{e^x} - {e^{ - x}}}}{2}$ and the value of $\cosh x = \dfrac{{{e^x} + {e^{ - x}}}}{2}$
Then, we can write the hyperbolic function of tangent as
$\tanh x = \dfrac{{\dfrac{{{e^x} - {e^{ - x}}}}{2}}}{{\dfrac{{{e^x} + {e^{ - x}}}}{2}}} = \dfrac{{{e^x} - {e^{ - x}}}}{{{e^x} + {e^{ - x}}}}$
We will plot the graph of $\tanh x$ to identify the nature of the function.
We can see that as the value of $x$ increases, then the value of $\tanh x$ also increases.
Therefore, the graph of the hyperbolic tangent function for all real values is strictly increasing.
Note:
The value of $\tanh x = \dfrac{{{e^x} - {e^{ - x}}}}{{{e^x} + {e^{ - x}}}}$. When $x$tends to infinity, $\tanh x$ tends to 1 such as
$
\mathop {\lim }\limits_{x \to \infty } \tanh x = \mathop {\lim }\limits_{x \to \infty } \dfrac{{{e^x} - {e^{ - x}}}}{{{e^x} + {e^{ - x}}}} \\
= \mathop {\lim }\limits_{x \to \infty } \dfrac{{\left( {1 - {e^{ - 2x}}} \right)}}{{\left( {1 + {e^{ - 2x}}} \right)}} \\
= \dfrac{{1 - \mathop {\lim }\limits_{x \to \infty } {e^{ - 2x}}}}{{1 + \mathop {\lim }\limits_{x \to \infty } {e^{ - 2x}}}} \\
= 1 \\
$
Similarly, when $x$ tends to $ - \infty $, the value of $\tanh x$ tends to $ - 1$. Then, we can say that the value becomes almost the same for higher or lower values of $x$.
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