Question

The genotypic ratio of a monohybrid cross will be
(a) 3:1
(b) 1:1:1
(c) 1:2:1
(d) 2:1

Answer 1

Hint: Monohybrid crosses are between two subjects with homozygous genotype or genotype with completely dominant or recessive traits. Gregor Mendel made monohybrid crosses for seven traits and followed their alternative forms and in all cases, the dominant form appeared in ${{F}_{1}}$ generation, and in ${{F}_{2}}$ both dominant and recessive appeared.

Complete step by step answer:
Monohybrid cross is a cross when only one trait and its two alternative forms are considered during hybridization experiment: The purple- flowered male plant is crossed with the white- flowered female plant. Tall male plant is crossed with the dwarf female plant.
Steps in Monohybrid cross: Trait: Height of plant: TallVs Dwarf Testing of parental plants for purity.
Monohybrid Cross between tall male plant and female dwarf plant and Vice Versa
${{F}_{1}}$ Generation – All plants were tall (Dwarfness disappeared) .
${{F}_{2}}$ Generation – Tall and dwarf plants both appeared in a ratio of approximately 3:1.
${{F}_{3}}$ Generation – Of the tall plants of ${{F}_{2}}$ some plants gave tall and some segregated again into Tall and Dwarf in 3:1 ratio and dwarf plant gave only dwarf plant.
${{F}_{4}}$ Generation – Some tall plants of ${{F}_{3}}$ generation given tall only and some again segregated in 3:1 ratio.

Mendel’s conclusion based on monohybrid cross:
Something is transferred from one generation to another, which carries information for expression of the trait. This something is particulate in nature. Mendel called this particulate thing as Factor or DeterminerMendelian factor is now termed as a gene.
- Genes are present in a linear fashion on specific loci(position) on homologous chromosomes in pairs each gene exist in two forms or alleles and govern the expression of alternative phenotypes (Allelomorphs ) such as Tall and Dwarf
In conclusion, the basic probability as it relates to Mendelian genetics. Mendel’s Law of segregation states that monohybrid cross for genotypic ratio 1:2:1 and phenotypic ratio is 3: 1.
Besides that Mendel’s Law Of Independent Assortment describes the outcome of dihybrid crosses for phenotypic ratio 9:3:3:1.
So, the correct answer is, ‘(c) 1:2:1.’

Note:
- Monohybrid cross is a cross that involves individuals and the examination of a single physical character in the next generation.
- Chi- square test is used to predict the monohybrid and dihybrid crosses by collecting and analysing the square test fitness. The most important step to reach accurate and precise outcomes of monohybrid and dihybrid crosses is to use the same types of objects in probability tests.