
The general formula of an ester (where R represents an alkyl group) is:
(A) ${\text{R - OH}}$
(B) ${\text{R - COOH}}$
(C) ${\text{R - COOR}}$
(D) ${\text{R - H}}$
Answer
569.1k+ views
Hint: The naturally occurring chemical substances that are formed by combination of an acid and an alcohol are known as esters. Esters are organic in nature.
Step by step answer: The functional group of an alcohol is ${\text{ - OH}}$. Thus, ${\text{R - OH}}$ is a general formula of an alcohol.
Thus, option (A) is not correct.
The functional group of an acid is ${\text{ - COOH}}$. Thus, ${\text{R - COOH}}$ is a general formula of an acid.
Thus, option (B) is not correct.
Esters are formed by the combination of an acid and an alcohol. Thus, the general formula of an ester is ${\text{R - COOR}}$.
Thus, option (C) is correct.
Adding a hydrogen atom to an alkyl group gives the parent alkane. Thus, the general formula ${\text{R - H}}$ is for an alkane.
Thus, option (D) is not correct.
Thus, the correct option is (C) ${\text{R - COOR}}$.
Additional Information: The general reaction for formation of an ester by combination of an acid and an alcohol is as follows:
${\text{R - OH + R - COOH}} \to {\text{R - COOR + }}{{\text{H}}_2}{\text{O}}$
In the reaction, a water molecule is eliminated.
The reaction of propanol and methanoic acid produces an ester named propyl methanoate. The reaction is as follows:
${\text{C}}{{\text{H}}_{\text{3}}}{\text{ - C}}{{\text{H}}_{\text{2}}}{\text{ - C}}{{\text{H}}_{\text{2}}}{\text{ - OH + H - COOH }} \to {\text{ C}}{{\text{H}}_{\text{3}}}{\text{ - C}}{{\text{H}}_{\text{2}}}{\text{ - C}}{{\text{H}}_{\text{2}}}{\text{ - COOH + }}{{\text{H}}_2}{\text{O}}$
Note: When esters are named, name the alcoholic group first, then name the acid group with –oate ending.
In ${\text{C}}{{\text{H}}_{\text{3}}}{\text{ - C}}{{\text{H}}_{\text{2}}}{\text{ - C}}{{\text{H}}_{\text{2}}}{\text{ - COOH}}$, the alcoholic group is propyl and the acid group is methane. In the acid group, replace –e with –oate. Thus, the name of the ester is propyl methanoate.
Other example of ester is ethyl propanoate ${\text{C}}{{\text{H}}_{\text{3}}}{\text{ - C}}{{\text{H}}_{\text{2}}}{\text{ - COO - C}}{{\text{H}}_2}{\text{ - C}}{{\text{H}}_3}$. Ethyl propanoate is formed by the reaction of ethanol $\left( {{\text{C}}{{\text{H}}_{\text{3}}}{\text{C}}{{\text{H}}_{\text{2}}}{\text{ - OH}}} \right)$ with propanoic acid $\left( {{\text{C}}{{\text{H}}_{\text{3}}}{\text{C}}{{\text{H}}_{\text{2}}}{\text{ - COOH}}} \right)$.
Step by step answer: The functional group of an alcohol is ${\text{ - OH}}$. Thus, ${\text{R - OH}}$ is a general formula of an alcohol.
Thus, option (A) is not correct.
The functional group of an acid is ${\text{ - COOH}}$. Thus, ${\text{R - COOH}}$ is a general formula of an acid.
Thus, option (B) is not correct.
Esters are formed by the combination of an acid and an alcohol. Thus, the general formula of an ester is ${\text{R - COOR}}$.
Thus, option (C) is correct.
Adding a hydrogen atom to an alkyl group gives the parent alkane. Thus, the general formula ${\text{R - H}}$ is for an alkane.
Thus, option (D) is not correct.
Thus, the correct option is (C) ${\text{R - COOR}}$.
Additional Information: The general reaction for formation of an ester by combination of an acid and an alcohol is as follows:
${\text{R - OH + R - COOH}} \to {\text{R - COOR + }}{{\text{H}}_2}{\text{O}}$
In the reaction, a water molecule is eliminated.
The reaction of propanol and methanoic acid produces an ester named propyl methanoate. The reaction is as follows:
${\text{C}}{{\text{H}}_{\text{3}}}{\text{ - C}}{{\text{H}}_{\text{2}}}{\text{ - C}}{{\text{H}}_{\text{2}}}{\text{ - OH + H - COOH }} \to {\text{ C}}{{\text{H}}_{\text{3}}}{\text{ - C}}{{\text{H}}_{\text{2}}}{\text{ - C}}{{\text{H}}_{\text{2}}}{\text{ - COOH + }}{{\text{H}}_2}{\text{O}}$
Note: When esters are named, name the alcoholic group first, then name the acid group with –oate ending.
In ${\text{C}}{{\text{H}}_{\text{3}}}{\text{ - C}}{{\text{H}}_{\text{2}}}{\text{ - C}}{{\text{H}}_{\text{2}}}{\text{ - COOH}}$, the alcoholic group is propyl and the acid group is methane. In the acid group, replace –e with –oate. Thus, the name of the ester is propyl methanoate.
Other example of ester is ethyl propanoate ${\text{C}}{{\text{H}}_{\text{3}}}{\text{ - C}}{{\text{H}}_{\text{2}}}{\text{ - COO - C}}{{\text{H}}_2}{\text{ - C}}{{\text{H}}_3}$. Ethyl propanoate is formed by the reaction of ethanol $\left( {{\text{C}}{{\text{H}}_{\text{3}}}{\text{C}}{{\text{H}}_{\text{2}}}{\text{ - OH}}} \right)$ with propanoic acid $\left( {{\text{C}}{{\text{H}}_{\text{3}}}{\text{C}}{{\text{H}}_{\text{2}}}{\text{ - COOH}}} \right)$.
Recently Updated Pages
Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Trending doubts
What are the major means of transport Explain each class 12 social science CBSE

Which are the Top 10 Largest Countries of the World?

Draw a labelled sketch of the human eye class 12 physics CBSE

Explain sex determination in humans with line diag class 12 biology CBSE

Explain sex determination in humans with the help of class 12 biology CBSE

Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE

