Answer
Verified
390.3k+ views
Hint: In this problem we are going to count the number of shaded rectangles from the given diagram. From the whole rectangle we are going to find only the shaded part. Thus, this question is based on part-whole. Part-whole is a ratio or a fraction that represents a relationship between a part and its whole.
Complete step-by-step solution:
From the above diagram, we can get
The total number of rectangle is \[3\]
Count the number of fully shaded rectangle is \[2\]
Out of \[3\], \[2\] rectangles are fully shaded and only the half of the last rectangle is shaded. In mathematics full is represented by the number \[1\], and the half is represented in fraction as \[\dfrac{1}{2}\].
So, the total shaded area \[ = 2 + \dfrac{1}{2}\]
Here we want to add two numbers, where the first number is a natural number and the other is fraction. To add both the numbers let convert the natural number into fraction. When there is no denominator for a number we can say that the denominator is \[1\], because any number divided by \[1\] is the number itself.
The total shaded area \[ = \dfrac{2}{1} + \dfrac{1}{2} = \dfrac{{2(2) + 1}}{2}\]
\[ = \dfrac{{4 + 1}}{2}\]
Total shaded area \[ = \dfrac{5}{2}\]
Here, the fraction is in improper fraction so let convert it into mixed fraction, we will get,
Therefore, the total shaded area is \[2\dfrac{1}{2}\]
Hence, option (c) is the correct answer.
Note: A fraction is a part of a whole. When the question is in a mixed fraction we should change it into an improper fraction and then only start to simplify. If the answer we get is in an improper fraction, finally we should change it into a mixed fraction.
Complete step-by-step solution:
From the above diagram, we can get
The total number of rectangle is \[3\]
Count the number of fully shaded rectangle is \[2\]
Out of \[3\], \[2\] rectangles are fully shaded and only the half of the last rectangle is shaded. In mathematics full is represented by the number \[1\], and the half is represented in fraction as \[\dfrac{1}{2}\].
So, the total shaded area \[ = 2 + \dfrac{1}{2}\]
Here we want to add two numbers, where the first number is a natural number and the other is fraction. To add both the numbers let convert the natural number into fraction. When there is no denominator for a number we can say that the denominator is \[1\], because any number divided by \[1\] is the number itself.
The total shaded area \[ = \dfrac{2}{1} + \dfrac{1}{2} = \dfrac{{2(2) + 1}}{2}\]
\[ = \dfrac{{4 + 1}}{2}\]
Total shaded area \[ = \dfrac{5}{2}\]
Here, the fraction is in improper fraction so let convert it into mixed fraction, we will get,
Therefore, the total shaded area is \[2\dfrac{1}{2}\]
Hence, option (c) is the correct answer.
Note: A fraction is a part of a whole. When the question is in a mixed fraction we should change it into an improper fraction and then only start to simplify. If the answer we get is in an improper fraction, finally we should change it into a mixed fraction.
Recently Updated Pages
Identify the feminine gender noun from the given sentence class 10 english CBSE
Your club organized a blood donation camp in your city class 10 english CBSE
Choose the correct meaning of the idiomphrase from class 10 english CBSE
Identify the neuter gender noun from the given sentence class 10 english CBSE
Choose the word which best expresses the meaning of class 10 english CBSE
Choose the word which is closest to the opposite in class 10 english CBSE
Trending doubts
A rainbow has circular shape because A The earth is class 11 physics CBSE
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Which are the Top 10 Largest Countries of the World?
Change the following sentences into negative and interrogative class 10 english CBSE
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
Write a letter to the principal requesting him to grant class 10 english CBSE