
The equivalent resistance between A and B is:
A. $\dfrac{{8R}}{5}$
B. $\dfrac{{5R}}{8}$
C. \[\dfrac{{3R}}{8}\]
D. $\dfrac{{7R}}{8}$
Answer
544.2k+ views
Hint: To solve this question, we need to identify the series and the parallel combinations of the resistances from the arrangement of the resistances given in the figure. As we combine the resistances, the circuit will be reduced and therefore become simplified.
Complete step by step answer:
As is clearly visible in the given figure, the rightmost two resistors of $R$ resistance each are connected in the series combination. So their equivalent resistance is given by
${R_1} = R + R$
$ \Rightarrow {R_1} = 2R$
So the given circuit is reduced to
Now, we can see that the rightmost two resistors of resistances $R$ and $2R$ are connected in the parallel combination. So their equivalent resistance is given by
$\dfrac{1}{{{R_2}}} = \dfrac{1}{R} + \dfrac{1}{{2R}}$
$ \Rightarrow \dfrac{1}{{{R_2}}} = \dfrac{3}{{2R}}$
Taking the reciprocal, we get
${R_2} = \dfrac{{2R}}{3}$
So, the above circuit reduces to
Now, let us label the bottom point as C. So the potentials across all the resistors can be shown as in the figure below.
From the potentials across the resistors, we can say that the resistances of $R$ and $\dfrac{{2R}}{3}$ are connected in series combination with each other. So their equivalent resistance is given by
${R_3} = R + \dfrac{{2R}}{3}$
$ \Rightarrow {R_3} = \dfrac{{5R}}{3}$
Also, this series combination is connected in parallel combination with the resistance of $R$. So the equivalent resistance is given by
$\dfrac{1}{{{R_4}}} = \dfrac{3}{{5R}} + \dfrac{1}{R}$
$ \Rightarrow \dfrac{1}{{{R_4}}} = \dfrac{8}{{5R}}$
Taking the reciprocal, we finally get
${R_4} = \dfrac{{5R}}{8}$
Thus, the equivalent resistance of the given combination of the resistors between A and B is equal to $\dfrac{{5R}}{8}$.
Hence, the correct answer is option B.
Note: For identifying the series combination between two resistors, we must ensure that the current flowing through one must not be divided before reaching the other. That is, the same current must flow through both of them. And for the parallel combination between two resistors, we must ensure that they both must have the same potential difference across them.
Complete step by step answer:
As is clearly visible in the given figure, the rightmost two resistors of $R$ resistance each are connected in the series combination. So their equivalent resistance is given by
${R_1} = R + R$
$ \Rightarrow {R_1} = 2R$
So the given circuit is reduced to
Now, we can see that the rightmost two resistors of resistances $R$ and $2R$ are connected in the parallel combination. So their equivalent resistance is given by
$\dfrac{1}{{{R_2}}} = \dfrac{1}{R} + \dfrac{1}{{2R}}$
$ \Rightarrow \dfrac{1}{{{R_2}}} = \dfrac{3}{{2R}}$
Taking the reciprocal, we get
${R_2} = \dfrac{{2R}}{3}$
So, the above circuit reduces to
Now, let us label the bottom point as C. So the potentials across all the resistors can be shown as in the figure below.
From the potentials across the resistors, we can say that the resistances of $R$ and $\dfrac{{2R}}{3}$ are connected in series combination with each other. So their equivalent resistance is given by
${R_3} = R + \dfrac{{2R}}{3}$
$ \Rightarrow {R_3} = \dfrac{{5R}}{3}$
Also, this series combination is connected in parallel combination with the resistance of $R$. So the equivalent resistance is given by
$\dfrac{1}{{{R_4}}} = \dfrac{3}{{5R}} + \dfrac{1}{R}$
$ \Rightarrow \dfrac{1}{{{R_4}}} = \dfrac{8}{{5R}}$
Taking the reciprocal, we finally get
${R_4} = \dfrac{{5R}}{8}$
Thus, the equivalent resistance of the given combination of the resistors between A and B is equal to $\dfrac{{5R}}{8}$.
Hence, the correct answer is option B.
Note: For identifying the series combination between two resistors, we must ensure that the current flowing through one must not be divided before reaching the other. That is, the same current must flow through both of them. And for the parallel combination between two resistors, we must ensure that they both must have the same potential difference across them.
Recently Updated Pages
Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Biology: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Basicity of sulphurous acid and sulphuric acid are

Master Class 12 Business Studies: Engaging Questions & Answers for Success

Trending doubts
How much time does it take to bleed after eating p class 12 biology CBSE

Explain sex determination in humans with line diag class 12 biology CBSE

Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE

When was the first election held in India a 194748 class 12 sst CBSE

Explain sex determination in humans with the help of class 12 biology CBSE

December 10th of 1948 is an important day in the history class 12 sst CBSE

