Question

The EMF induced in a coil of wire, which is rotating in a magnetic field, does not depend on:

Answer 1

Hint: When a bar magnet is pulled in and out of the coil, an EMF is created. Motion in opposite directions produces opposite-sign EMFs, which may likewise be reversed by reversing poles. When the coil is moved instead of the magnet, the same effects are obtained; it is the relative motion that matters.

Complete step-by-step solution:
EMF does not depend on the resistance of the circuit.
As we know that,
EMF Induced =- the rate of change of flux
i.e., \[e = - \Delta \phi \]
where, \[\phi = BA\cos \theta \]
\[\phi = \]Magnetic Flux
\[A = \] Area
\[B = \] Magnetic Field
\[\theta = \]Angle
Therefore from the above formula, we get to know that EMF induced depends on angular speed of rotation (as in the question coil is rotating), on the area of the coil.
Also, \[\phi = NBA\cos \theta \] - Flux Linkage
\[\phi = NBAw.\sin wt\] - at \[t\]
Therefore from the above, we also get to know that EMF induced also depends upon no turns and angular speed.
So, EMF does not depend on the Resistance of the coil.

Note:
> The galvanometer needle deflects as the magnet is shifted, indicating that the current is flowing through the coil. When the magnet is moved in one direction (for example, into the coil), the needle deflects in that direction; when the magnet is moved in the opposite direction (for example, out of the coil), the needle deflects in the other direction. A moving magnet can not only cause a current to flow in the coil, but the direction of the current also depends on the direction of the current.
> No current will flow through the coil if the magnet is held motionless near, or even inside, the coil.