Question

The element with atomic number $33$ belongs to:
A.Group $13$
B.Group $14$
C.Group $15$
D.Group $16$

Answer 1

Hint: We must remember that the elements are arranged in increasing atomic numbers and the elements with similar properties fall in the same vertical column as the periodic table. The group of elements or family of elements fall in the same column and they resemble one another in their properties.

Complete answer:
As we know that the elements arranged in vertical columns are called groups in the periodic table. There are $18$ groups in the periodic table and each element in the group are analogous to one another.
Atomic number $33$, outermost electronic configuration is \[3{d^{10}}4{s^2}{p^5}\].
Let us see the options one by one to find the correct answer,
Group $13$ elements outer most electronic configuration is $3{d^{10}}4{s^2}{p^1}$.
Group $14$ elements outermost electronic configuration is \[3{d^{10}}4{s^2}{p^2}\].
Group $15$ elements outer most electronic configuration is $3{d^{10}}4{s^2}{p^3}$.
Group $16$ elements outer most electronic configuration is $3{d^{10}}4{s^2}{p^4}$.
Atomic number $33$, outermost electronic configuration is \[3{d^{10}}4{s^2}{p^5}\] and group $15$ elements outer most electronic configuration is $3{d^{10}}4{s^2}{p^3}$ $(10 + 2 + 3 = 15)$ .
From the above data, option C. Group $15$ is the correct answer and the atomic number $33$ belongs to Group $15$.

Additional information:
Dimitri Mendeleev, Russian chemist and Julius Lothar, German chemist, independently published the periodic table in 1869 and 1870, respectively. Dimitri Mendeleev arranged the periodic table by atomic masses and he predicted and left spaces in his periodic table for the discovery of other elements.

Note:
We have to remember the atomic number $33$ is an arsenic. If we add the electrons in an orbitals of outermost electronic configuration, the sum resembles the group number. For example group number $3$ outermost electronic configuration is \[3{d^1}4{s^2}\] , the electrons count is $(1 + 2 = 3)$ three.