Question

The electrostatic potential energy of a charge of 5 C at a point in the electrostatic field is 50 J. The potential at that point is?
(A) 0.1 V
(B) 5 V
(C) 10 V
(D) 250 V

Answer 1

Hint:We are given the electrostatics potential energy of a charge whose magnitude of charge is 5C. we need to find out the value of electric potential at that point. We know that in bringing charge from one point to another in absence of any external field no work is done but if there is some field present then work is to be done in order to overcome the barrier. So, we can make use of the relation of the potential energy and electric potential.

Formula used:
$W=Vq$
where W is the potential energy and V is the electric potential.

Complete step by step answer:
Electric potential is defined as the amount of work needed to move a unit charge from a reference point to a specific point against the electric field. When an object is moved against the electric field it gains some amount of energy which is defined as the electric potential energy. The electric potential of the charge is obtained by dividing the potential energy by the quantity of charge.

Given quantities, $W=50J$ and $q=5C$, so using the above-mentioned formula we get,
$V=\dfrac{W}{q}$
$\Rightarrow V=\dfrac{50}{5}$
$\therefore V=10V$
So, the potential comes out to be 10 Volts.

So, the correct option is C.

Note: In general if we have to find the value of electric potential due to some charge, we know electric potential is given by the formula: \[V=k\dfrac{Q}{r}\], where Q is the charge and r is the distance between the charge and the point where the potential is to be determined and k is a constant whose value is \[k=9\times {{10}^{9}}N{{m}^{2}}/{{C}^{2}}\]. While finding the electric potential we have to take some reference point and the value of electric potential is taken to be zero at infinity.