Questions & Answers

Question

Answers

A.333

B.323

C.313

D.303

Answer

Verified

128.7k+ views

We are given that the divisor when the quotient, dividend, and the remainder are respectively 547, 171282, and 71.

Let us assume that \[x\] be the divisor.

Using the formula, \[{\text{Dividend}} = {\text{Divisor}} \cdot {\text{Quotient + Remainder}}\] in the given values, we get

\[

\Rightarrow 171282 = x \times 547 + 71 \\

\Rightarrow 171282 = 547x + 71 \\

\]

Subtracting the above equation by 71 on both sides, we get

\[

\Rightarrow 171282 - 71 = 547x + 71 - 71 \\

\Rightarrow 171211 = 547x \\

\]

Dividing the above equation by 547 on both sides, we get

\[

\Rightarrow \dfrac{{171211}}{{547}} = \dfrac{{547x}}{{547}} \\

\Rightarrow 313 = x \\

\Rightarrow x = 313 \\

\]

Thus, the required divisor is 313.

Hence,