Question

The distance between Akash's school and home is \[2km\,\,385\,m\]. Every day, he walks to and from the school. Calculate the total distance covered by him from Monday to Friday.
1. \[23\,km\,\,870\,m\]
2. \[23\,km\,\,850\,m\]
3. \[21\,km\,\,860\,m\]
4. \[20\,km\,\,850\,m\]

Answer 1

Hint: Here the question is a word problem. The question is related to the distance topic. In the question they have mentioned the distance between the school and home of Akash. By using simple arithmetic operations we are going to solve the given problem.

Complete step-by-step answer:
In mathematics we have four kinds of arithmetic operations namely, addition, subtraction, multiplication, and division.
Now consider the question.
The distance between Akash’s school and home = \[2km\,\,385\,m\]
Then the total distance covered by him, from school to home and home to school will be twice of the distance travelled by Akash's school and home.
Therefore the total distance covered by the Akash = \[2 \times \left( {2km\,\,385\,m} \right)\]
On multiplying we get
\[ \Rightarrow 4km\,\,770\,m\]
Therefore the total distance covered by Akash each day = \[4km\,\,770\,m\]
We had determined the distance covered by the Akash per day. In the question they have asked to determine the distance covered by Akash from Monday to Friday.
From Monday to Friday we have 5 days.
So now we must determine the distance covered by Akash for 5 days.
To determine this we multiply 5 to the total distance covered by Akash per day.
Now we have
\[ \Rightarrow 5 \times \left( {4km\,\,770\,m} \right)\]
On multiplying we have
\[ \Rightarrow 23km\,\,850\,m\]
Therefore the option (B) is the correct one.
So, the correct answer is “Option B”.

Note: This problem can be solved in another way also. We can convert the given quantity into meters and hence we can obtain the required solution.
Consider the given question.
\[2km\,\,385\,m\]
As we know that \[1km\, = \,1000\,m\], by considering this the above quantity can be written as
\[ \Rightarrow 2385\,m\]
The total distance covered by the Akash for one day = \[2 \times \left( {2385\,m} \right) = 4770\,m\]
The total distance covered by the Akash for five days = \[5 \times \left( {4770\,m} \right) = 23,850\,m\]
When we divide by 1,000. It is converted to Km.
So we have
\[ \Rightarrow 23km\,\,850\,m\]
Any of the methods is the correct one.