
The de-Broglie wavelength of a neutron at \[{27^o}C\] is $\lambda $ . What will be its wavelength at \[{927^o}C\]?
A. $\dfrac{\lambda }{2}$
B. $\dfrac{\lambda }{3}$
C. $\dfrac{\lambda }{4}$
D. $\dfrac{\lambda }{9}$
Answer
558.6k+ views
Hint: Use the de Broglie wavelength equation. Express the momentum in terms of kinetic energy. Substitute kinetic energy with the equation of energy of thermal neutrons.
Complete step by step answer:
Let ${T_1} = {27^o}C = 300K$ and ${T_2} = {927^o}C = 1200K$
Then the corresponding de Broglie wavelength will be ${\lambda _1}$ and ${\lambda _2}$
Thus for the first case
${\lambda _1} = \dfrac{h}{{\sqrt {3mk{T_1}} }}$
Then for the second case
${\lambda _2} = \dfrac{h}{{\sqrt {3mk{T_2}} }}$
We divide both equations and cancel the common terms.
After that we get the following ratio
$\dfrac{{{\lambda _1}}}{{{\lambda _2}}} = \sqrt {\dfrac{{{T_2}}}{{{T_1}}}} $
Thus the required wavelength will be
\[{\lambda _2} = \sqrt {\dfrac{{{T_1}}}{{{T_2}}}} \lambda = \sqrt {\dfrac{{300}}{{1200}}} \lambda = \dfrac{\lambda }{2}\]
So, the correct answer is “Option A”.
Additional Information:
De Broglie wavelength is expressed as Planck's constant divided by momentum. It states that every particle in this universe removes in a wave like pattern. However for some particles the speed is very less. Thus the momentum is less and thus the wavelength is very large. The wavelength is so large that the object is seen as moving in a straight line unlike that of a wave like manner. However for objects moving with a very high speed, such a speed that is comparable to the speed of light, the momentum increases and the wavelength decreases. Hence we can clearly see the particles moving in a wave like pattern. Normally larger objects move with a larger wavelength and small objects move with a smaller and evident wavelength.
Note:
Students should learn the different ways the kinetic energy can be expressed. Some questions demand other expressions for momentum as well as kinetic energy. Also do carefully cancel the terms.
The wavelength is so large that the object is seen as moving in a straight line unlike that of a wave like manner.
Complete step by step answer:
Let ${T_1} = {27^o}C = 300K$ and ${T_2} = {927^o}C = 1200K$
Then the corresponding de Broglie wavelength will be ${\lambda _1}$ and ${\lambda _2}$
Thus for the first case
${\lambda _1} = \dfrac{h}{{\sqrt {3mk{T_1}} }}$
Then for the second case
${\lambda _2} = \dfrac{h}{{\sqrt {3mk{T_2}} }}$
We divide both equations and cancel the common terms.
After that we get the following ratio
$\dfrac{{{\lambda _1}}}{{{\lambda _2}}} = \sqrt {\dfrac{{{T_2}}}{{{T_1}}}} $
Thus the required wavelength will be
\[{\lambda _2} = \sqrt {\dfrac{{{T_1}}}{{{T_2}}}} \lambda = \sqrt {\dfrac{{300}}{{1200}}} \lambda = \dfrac{\lambda }{2}\]
So, the correct answer is “Option A”.
Additional Information:
De Broglie wavelength is expressed as Planck's constant divided by momentum. It states that every particle in this universe removes in a wave like pattern. However for some particles the speed is very less. Thus the momentum is less and thus the wavelength is very large. The wavelength is so large that the object is seen as moving in a straight line unlike that of a wave like manner. However for objects moving with a very high speed, such a speed that is comparable to the speed of light, the momentum increases and the wavelength decreases. Hence we can clearly see the particles moving in a wave like pattern. Normally larger objects move with a larger wavelength and small objects move with a smaller and evident wavelength.
Note:
Students should learn the different ways the kinetic energy can be expressed. Some questions demand other expressions for momentum as well as kinetic energy. Also do carefully cancel the terms.
The wavelength is so large that the object is seen as moving in a straight line unlike that of a wave like manner.
Recently Updated Pages
A man running at a speed 5 ms is viewed in the side class 12 physics CBSE

The number of solutions in x in 02pi for which sqrt class 12 maths CBSE

State and explain Hardy Weinbergs Principle class 12 biology CBSE

Write any two methods of preparation of phenol Give class 12 chemistry CBSE

Which of the following statements is wrong a Amnion class 12 biology CBSE

Differentiate between action potential and resting class 12 biology CBSE

Trending doubts
What are the major means of transport Explain each class 12 social science CBSE

Which are the Top 10 Largest Countries of the World?

Draw a labelled sketch of the human eye class 12 physics CBSE

Explain sex determination in humans with line diag class 12 biology CBSE

Explain sex determination in humans with the help of class 12 biology CBSE

Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE

