
The current through a 60W lamp rated for 250V is
A) 0.24A
B) 4.2A
C) 0.5A
D) 6A
Answer
561.3k+ views
Hint: In this question, power and voltage is given we have to find out the value of current. For this we use the formula which relates the power, voltage and current i.e. $ P = VI $ , on substituting the values we can easily find the value of current.
Complete step by step solution
As, it is given that
Power of the lamp is $ P = 60W $
And the voltage across the lamp is $ V = 250V $
We have to find the value of current.
For this, we know that the power is equal to the product of voltage and current. Therefore, we can write it as $ P = VI $
P is power of the lamp and V is the voltage across the lamp and I is the current passing through the lamp.
We can write above formula as $ I = \dfrac{P}{V} $
Now, substitute the given values of P and V in above equation, we get
$ \Rightarrow I = \dfrac{{60}}{{250}} $
$ \Rightarrow I = 0.24A $
Hence, the current through a 60W lamp of rated 250V is 0.24A.
Therefore, option A is correct.
Note:
Electrical power is defined as the rate of consumption of energy or the rate of doing work i.e. $ power = \dfrac{{work}}{{time}} $
And we also know that the work done by current I when it flows in potential V at time t is $ W = VIt $
On substituting this value in the formula of power, we get
$ \Rightarrow P = \dfrac{{VIt}}{t} = VI $
In this way we can derive the expression of power.
Complete step by step solution
As, it is given that
Power of the lamp is $ P = 60W $
And the voltage across the lamp is $ V = 250V $
We have to find the value of current.
For this, we know that the power is equal to the product of voltage and current. Therefore, we can write it as $ P = VI $
P is power of the lamp and V is the voltage across the lamp and I is the current passing through the lamp.
We can write above formula as $ I = \dfrac{P}{V} $
Now, substitute the given values of P and V in above equation, we get
$ \Rightarrow I = \dfrac{{60}}{{250}} $
$ \Rightarrow I = 0.24A $
Hence, the current through a 60W lamp of rated 250V is 0.24A.
Therefore, option A is correct.
Note:
Electrical power is defined as the rate of consumption of energy or the rate of doing work i.e. $ power = \dfrac{{work}}{{time}} $
And we also know that the work done by current I when it flows in potential V at time t is $ W = VIt $
On substituting this value in the formula of power, we get
$ \Rightarrow P = \dfrac{{VIt}}{t} = VI $
In this way we can derive the expression of power.
Recently Updated Pages
Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Business Studies: Engaging Questions & Answers for Success

Trending doubts
Which are the Top 10 Largest Countries of the World?

What are the major means of transport Explain each class 12 social science CBSE

Draw a labelled sketch of the human eye class 12 physics CBSE

Why cannot DNA pass through cell membranes class 12 biology CBSE

Differentiate between insitu conservation and exsitu class 12 biology CBSE

Draw a neat and well labeled diagram of TS of ovary class 12 biology CBSE

