Solve the given equation. State the number and type of roots.x^2+x-12=0

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Asked 6/2/2014 1:27:46 PM

Updated 6/27/2014 12:54:21 AM

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Edited by jeifunk [6/27/2014 12:54:19 AM]

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Question

Asked 6/2/2014 1:27:46 PM

Updated 6/27/2014 12:54:21 AM

1 Answer/Comment

This answer has been confirmed as correct and helpful.

Edited by jeifunk [6/27/2014 12:54:19 AM]

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x^2-5x-36=0

(x-9)(x+4)=0

x-9=0 or x+4=0

x=9 or x=-4

(x-9)(x+4)=0

x-9=0 or x+4=0

x=9 or x=-4

Added 6/23/2014 11:43:45 AM

This answer has been confirmed as correct and helpful.

Confirmed by jeifunk [6/23/2014 11:45:48 AM]

Use synthetic substitution to find g(3) and g (4) for the function g(x)=x^2-8x+6 . a. -9, -10 c. -19, -243 b. 14, -42 d. 55, 272 **Weegy:** The function g(x)=x^2-8x+6 has a value of -9, -10 if g(3) and g (4). Solution: g(3)=(3)^2-8(3)+6;
g(3) = 9 - 24 + 6;
g(3) = 9 - 18;
g(3) = -9 - - - - - - - - -
g(4) = (4)^2 - 8(4) + 6;
g(4) = 16 - 32 + 6;
g(4) = 16 - 26;
g(4) = -10 (More)

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Updated 6/2/2014 12:57:48 PM

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