Answer
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Hint: Find the volume of the wall and deduct \[10\% \] of the wall which is filled with mortar, and find the volume of a single brick and divide both to find the number of bricks used in the wall and find the cost using the condition given.
Complete step-by-step answer:
Given, Cost of 1000 bricks is Rs.350.
So, the cost of a single brick is \[Rs0.35\] .
Dimensions of a single brick is \[25cm \times 16cm \times 10cm\] ,
Here L = 25cm, B = 16cm, and W = 10cm.
Let’s use it and calculate the volume of the single brick.
So, the volume of a single brick is \[25cm*16cm*10cm = 4000c{m^3}\] .
Dimensions of the wall is \[24m \times 6m \times 0.4m\] ,
Here L = 25cm, B = 16cm, and W = 10cm.
Let’s use it and calculate the volume of the single brick.
So, the volume of the wall is \[24m*6m*0.4m = 57.6{m^3}\] .
Provided \[10\% \] of the wall is filled with mortar, so the volume of the mortar used in the wall is
\[ \Rightarrow 10\% {\rm{ }}of{\rm{ }}57.6\]
\[ \Rightarrow \dfrac{{10}}{{100}}*57.6\]
\[ \Rightarrow 5.76{m^3}\]
So, the volume of the mortar used in the wall is \[5.76{m^3}\] .
So, the volume of the bricks used in the wall is \[57.6{m^3} - 5.76{m^3} = 51.84{m^3}\]
Number of bricks used in the wall= (Volume of the wall excluding \[10\% \] volume of mortar) / (Volume of a single brick).
Number of bricks used in the wall is,
\[ \Rightarrow \dfrac{{51.84{m^3}}}{{4000c{m^3}}}\]
\[ \Rightarrow \dfrac{{51.84 \times 1000000}}{{4000}}\]
\[ \Rightarrow 12960Bricks\]
So, 12960 bricks were used in the wall.
If 1000 bricks costs Rs.350, then 1 brick costs Rs. \[\dfrac{{350}}{{1000}}\] .
So, the cost of a single brick is \[Rs0.35\] .
So, the cost of 12960 bricks is=\[0.35 \times 12960 = Rs4536\] .
That means Option C is correct \[Rs4536\] .
Note: When \[n\] units cost \[Rs.x\] , then 1 unit costs \[Rs\dfrac{x}{n}\] . Wall contains bricks and mortar, to calculate the volume of bricks used, the volume of mortar has to be deducted for the exact volume of bricks used in the wall.
Complete step-by-step answer:
Given, Cost of 1000 bricks is Rs.350.
So, the cost of a single brick is \[Rs0.35\] .
Dimensions of a single brick is \[25cm \times 16cm \times 10cm\] ,
Here L = 25cm, B = 16cm, and W = 10cm.
Let’s use it and calculate the volume of the single brick.
So, the volume of a single brick is \[25cm*16cm*10cm = 4000c{m^3}\] .
Dimensions of the wall is \[24m \times 6m \times 0.4m\] ,
Here L = 25cm, B = 16cm, and W = 10cm.
Let’s use it and calculate the volume of the single brick.
So, the volume of the wall is \[24m*6m*0.4m = 57.6{m^3}\] .
Provided \[10\% \] of the wall is filled with mortar, so the volume of the mortar used in the wall is
\[ \Rightarrow 10\% {\rm{ }}of{\rm{ }}57.6\]
\[ \Rightarrow \dfrac{{10}}{{100}}*57.6\]
\[ \Rightarrow 5.76{m^3}\]
So, the volume of the mortar used in the wall is \[5.76{m^3}\] .
So, the volume of the bricks used in the wall is \[57.6{m^3} - 5.76{m^3} = 51.84{m^3}\]
Number of bricks used in the wall= (Volume of the wall excluding \[10\% \] volume of mortar) / (Volume of a single brick).
Number of bricks used in the wall is,
\[ \Rightarrow \dfrac{{51.84{m^3}}}{{4000c{m^3}}}\]
\[ \Rightarrow \dfrac{{51.84 \times 1000000}}{{4000}}\]
\[ \Rightarrow 12960Bricks\]
So, 12960 bricks were used in the wall.
If 1000 bricks costs Rs.350, then 1 brick costs Rs. \[\dfrac{{350}}{{1000}}\] .
So, the cost of a single brick is \[Rs0.35\] .
So, the cost of 12960 bricks is=\[0.35 \times 12960 = Rs4536\] .
That means Option C is correct \[Rs4536\] .
Note: When \[n\] units cost \[Rs.x\] , then 1 unit costs \[Rs\dfrac{x}{n}\] . Wall contains bricks and mortar, to calculate the volume of bricks used, the volume of mortar has to be deducted for the exact volume of bricks used in the wall.
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