Answer
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Hint: In this given question, we can use the unitary method of solving the question. In this method we may at first find the cost of the amount equal to a single unit and then multiply the required amount with it in order to get the cost of the required amount.
Complete step-by-step answer:
In this question, we are given that the cost of 1 kg of sugar is Rs.18 and we are asked to find out the cost of 250gms sugar.
We know that 1 kilogram is equal to 1000 grams.
So, the cost of 1kg sugar is equal to the cost of 1000gms sugar that is Rs.18.
This gives us that 1gm of sugar costs $Rs.\dfrac{18}{1000}$.
Now, we can obtain the cost of 250gms of sugar by multiplying 250 with the cost of 1gm of sugar \[\left( Rs.\dfrac{18}{1000} \right)\]. That is
$Rs.\dfrac{18}{1000}\times 250=Rs.\dfrac{18}{4}=Rs.4.5$
Hence, we have got the cost of 250gms sugar as Rs.4.5.
Therefore, the correct option to the given question is option (b) Rs.4.5.
Note: In this sort of question, we must be very much careful to convert the units into a single unit before calculations. Also, we may have converted 250gms into 0.25kg and used it in the calculations to arrive at the same answer as we have obtained above in the solution.
Complete step-by-step answer:
In this question, we are given that the cost of 1 kg of sugar is Rs.18 and we are asked to find out the cost of 250gms sugar.
We know that 1 kilogram is equal to 1000 grams.
So, the cost of 1kg sugar is equal to the cost of 1000gms sugar that is Rs.18.
This gives us that 1gm of sugar costs $Rs.\dfrac{18}{1000}$.
Now, we can obtain the cost of 250gms of sugar by multiplying 250 with the cost of 1gm of sugar \[\left( Rs.\dfrac{18}{1000} \right)\]. That is
$Rs.\dfrac{18}{1000}\times 250=Rs.\dfrac{18}{4}=Rs.4.5$
Hence, we have got the cost of 250gms sugar as Rs.4.5.
Therefore, the correct option to the given question is option (b) Rs.4.5.
Note: In this sort of question, we must be very much careful to convert the units into a single unit before calculations. Also, we may have converted 250gms into 0.25kg and used it in the calculations to arrive at the same answer as we have obtained above in the solution.
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