Courses
Courses for Kids
Free study material
Offline Centres
More
Store

# The compound interest on Rs. $100000$ at $20\%$ per annum for $2$ years $3$ months, compound annually is A.RS. $$151200$$B.Rs. $$100000$$C.Rs. $$51200$$D.Rs. $$251200$$

Last updated date: 13th Jun 2024
Total views: 401.4k
Views today: 8.01k
Verified
401.4k+ views
Hint: Here we need to find compound interest that to compound annually, so we have to find out first years interest then second years compound interest then remaining years interest. By these steps we can find out the final answer.

Given that $$P = 100000,\;r = 0.2$$​
(Converting $$2$$ years $$3$$ months to years) $$= n = 2.25$$
Interest is compounded annually,
For first year $$= 100000 \times 0.2 \times 1 = 20000$$
For second year $${P_{new}} = 120000$$
Interest $$= 120000 \times 0.2 \times 1 = 24000$$
For last $$0.25\;$$ year, $${P_{new}} = 144000$$
Interest $$= 144000 \times 0.2 \times 0.25 = 7200$$
New amount $$= 144000 + 7200 = 151200$$
Interest $$= 151200 - 100000 = 51200$$
Hence, the compound interest on Rs. $$100000$$ at $$20\%$$ per annum for $$2$$ years $$3$$ months, compound annually is $$= 151200 - 100000 = 51200$$.
Note: Usually on this type of question, we apply the formula for compound interest, but in this problem they asked to apply compound interest for $$2$$ years $$3$$ months, that too compounded annually, so we find compound interest for each year, then added them as principal amount for next year’s principle.