
The column graph, given above, shows the number of patients, examined by Dr. V.K.Bansal, on different days of a particular week.
Use the graph to answer the following:
On which days were an equal number of patients examined?
Answer
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Hint: First of all, we need to see how we read a graph. These long vertical rectangles are known as bars. In this question, the vertical axis represents the No. of Patients and the horizontal axis represents the Days. We first see the first day i.e. Sunday and reading off the height of the bar corresponding to the Sun. The value at the left represents the No. of Patients treated by Dr. V.K.Bansal on Sun. Similarly, we will see for each day we are given. We will then obtain the data of how many patients are treated by Dr. V.K.Bansal on each day and then we can see on which days, the No. of Patients treated were equal.
Complete answer: First of all, let us Compute from the graph how many patients are treated each day.
Now, we see that No. of Patients treated on Sun and Thurs are \[50\].
Hence, we can say that Equal No. of Patients were examined on Sun and Thu.
Note:
While reading the graph, we need to be careful about the length of the bars because even a minor difference in the length will change the answer. And, we need to see that we read the correct value corresponding to the days. We usually make mistakes while reading the values and mix up the values for different days. And, after finding each day, we must cross check it with the given graph once.
Complete answer: First of all, let us Compute from the graph how many patients are treated each day.
Now, we see that No. of Patients treated on Sun and Thurs are \[50\].
Hence, we can say that Equal No. of Patients were examined on Sun and Thu.
Note:
While reading the graph, we need to be careful about the length of the bars because even a minor difference in the length will change the answer. And, we need to see that we read the correct value corresponding to the days. We usually make mistakes while reading the values and mix up the values for different days. And, after finding each day, we must cross check it with the given graph once.
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