
The coefficient of \[{x^7}\] in the expression \[{(1 + x)^{10}} + x{(1 + x)^9} + {x^2}{(1 + x)^8}....... + {x^{10}}\] is
A) 210
B) 420
C) 120
D) 330
Answer
584.4k+ views
Hint:
Here we need to use both geometric progression and combination because we have to find the coefficient of that term. A term is made of a variable with the coefficient of that variable.
Complete step by step solution:
Given the series,
\[{(1 + x)^{10}} + x{(1 + x)^9} + {x^2}{(1 + x)^8}....... + {x^{10}}\]
Here common ratio r= \[\dfrac{{x{{(1 + x)}^9}}}{{{{(1 + x)}^{10}}}}\]
r\[ \Rightarrow \dfrac{x}{{1 + x}}\]
First term, \[a={(1 + x)^{10}}\]
Here there are 11 total terms.
Now sum of all these terms in G.P.is given by
S=\[a\dfrac{{1 - {r^n}}}{{1 - r}}\]
\[S = {(1 + x)^{10}}\left( {\dfrac{{1 - {{\left( {\dfrac{x}{{1 + x}}} \right)}^{11}}}}{{1 - \dfrac{x}{{1 + x}}}}} \right)\]
\[
\Rightarrow S = {(1 + x)^{10}}\left( {\dfrac{{\dfrac{{{{\left( {1 + x} \right)}^{11}} - {x^{11}}}}{{{{\left( {1 + x} \right)}^{11}}}}}}{{\dfrac{{1 + x - x}}{{1 + x}}}}} \right) \\
\Rightarrow S = {(1 + x)^{10}}\left( {\dfrac{{{{\left( {1 + x} \right)}^{11}} - {x^{11}}}}{{{{(1 + x)}^{10}}}}} \right) \\
\Rightarrow S = {\left( {1 + x} \right)^{11}} - {x^{11}} \\
\]
Now coefficient of \[{x^7}\] is given by
\[
11{C_7} = \dfrac{{11!}}{{7!\left( {11 - 7} \right)!}} \\
\Rightarrow \dfrac{{11!}}{{7!\left( 4 \right)!}} \\
\Rightarrow \dfrac{{11 \times 10 \times 9 \times 8}}{{24}} \\
\Rightarrow 330 \\
\]
So the coefficient of \[{x^7}\] is 330.
So option D is correct.
Note:
1) In a geometric progression except for the first term, other terms are obtained by multiplying the previous term with a fixed common ratio.
2) \[a,ar,a{r^2},.....\] is a geometric progression.
3) This common ratio is denoted by r and the first term is denoted by a.
4) If three positive numbers a, b, c are in G.P. then their geometric mean is b. such that \[b= \sqrt {ac} \].
5) An arithmetic progression is having a common difference d.
\[a,a + d,a + 2d....\] is an arithmetic progression.
Here we need to use both geometric progression and combination because we have to find the coefficient of that term. A term is made of a variable with the coefficient of that variable.
Complete step by step solution:
Given the series,
\[{(1 + x)^{10}} + x{(1 + x)^9} + {x^2}{(1 + x)^8}....... + {x^{10}}\]
Here common ratio r= \[\dfrac{{x{{(1 + x)}^9}}}{{{{(1 + x)}^{10}}}}\]
r\[ \Rightarrow \dfrac{x}{{1 + x}}\]
First term, \[a={(1 + x)^{10}}\]
Here there are 11 total terms.
Now sum of all these terms in G.P.is given by
S=\[a\dfrac{{1 - {r^n}}}{{1 - r}}\]
\[S = {(1 + x)^{10}}\left( {\dfrac{{1 - {{\left( {\dfrac{x}{{1 + x}}} \right)}^{11}}}}{{1 - \dfrac{x}{{1 + x}}}}} \right)\]
\[
\Rightarrow S = {(1 + x)^{10}}\left( {\dfrac{{\dfrac{{{{\left( {1 + x} \right)}^{11}} - {x^{11}}}}{{{{\left( {1 + x} \right)}^{11}}}}}}{{\dfrac{{1 + x - x}}{{1 + x}}}}} \right) \\
\Rightarrow S = {(1 + x)^{10}}\left( {\dfrac{{{{\left( {1 + x} \right)}^{11}} - {x^{11}}}}{{{{(1 + x)}^{10}}}}} \right) \\
\Rightarrow S = {\left( {1 + x} \right)^{11}} - {x^{11}} \\
\]
Now coefficient of \[{x^7}\] is given by
\[
11{C_7} = \dfrac{{11!}}{{7!\left( {11 - 7} \right)!}} \\
\Rightarrow \dfrac{{11!}}{{7!\left( 4 \right)!}} \\
\Rightarrow \dfrac{{11 \times 10 \times 9 \times 8}}{{24}} \\
\Rightarrow 330 \\
\]
So the coefficient of \[{x^7}\] is 330.
So option D is correct.
Note:
1) In a geometric progression except for the first term, other terms are obtained by multiplying the previous term with a fixed common ratio.
2) \[a,ar,a{r^2},.....\] is a geometric progression.
3) This common ratio is denoted by r and the first term is denoted by a.
4) If three positive numbers a, b, c are in G.P. then their geometric mean is b. such that \[b= \sqrt {ac} \].
5) An arithmetic progression is having a common difference d.
\[a,a + d,a + 2d....\] is an arithmetic progression.
Recently Updated Pages
Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Business Studies: Engaging Questions & Answers for Success

Trending doubts
Which are the Top 10 Largest Countries of the World?

What are the major means of transport Explain each class 12 social science CBSE

Draw a labelled sketch of the human eye class 12 physics CBSE

Why cannot DNA pass through cell membranes class 12 biology CBSE

Differentiate between insitu conservation and exsitu class 12 biology CBSE

Draw a neat and well labeled diagram of TS of ovary class 12 biology CBSE

