Question

The $Cl{O_2}$ reacts with ${O_3}$ to give:
A. $C{l_2}{O_4}$
B. $C{l_2}O$
C. $Cl{O_3}$
D. $Cl{O_4}$

Answer 1

Hint: ${O_3}$ is known as ozone which is an unstable compound in blue colour and is a diamagnetic gas. It helps in protecting the Earth from the intense ultraviolet radiations from the Sun. It is an allotropic molecule which tends to contain three atoms of oxygen. It tends to form hydrogen peroxide on reacting and dissolving in water.

Complete step by step solution:
 Now when we react the chlorine dioxide with the ozone the formation of $Cl{O_3}$ and oxygen takes place. So the reaction for it is the following: $Cl{O_2} + {O_3} \to Cl{O_3} + {O_2}$.
As we know that ozone is a strong bleaching agent because of its oxidation power. It has the ability to give oxygen as well as nascent oxygen. And this nascent oxygen causes the bleaching action because it tends to bleach the colour on the permanent basis. It tends to react even with the sites of unsaturation including those present in the aromatic rings. It is more soluble in the inert non polar solvents. Such as carbon tetrachloride. It also tends to act as a sterilizing agent. It acts as a bleaching agent for many vegetable colouring matters.

Hence the correct answer is option C.

Note: Ozone is considered as a toxic substance at low concentrations and can even explode at high concentrations. Remember that the bleaching action of ozone is based on its oxidation while that of sulphur is based on reduction. The factors which generally affect the ozone bleaching is pH, consistency, selectivity, efficiency and temperature.