
The charge on a hole is equal to the charge of
$ \left( A \right){\text{ zero}} $
$ \left( B \right){\text{ Proton}} $
$ \left( C \right){\text{ Neutron}} $
$ \left( D \right){\text{ Electron}} $
Answer
467.1k+ views
Hint: So in question, we have to tell you about the charge on a hole will be equal to what. So for this, we need to know the hole. So as we know that the hole is carrying a positive charge. And from this statement, we can now answer this question.
Complete step by step answer
At the point when an electron gets energized from the valence band to the conduction band, an opening is made. This is the age of the electron-opening pair. Additionally, when an electron makes a progress from the conduction band to the valence band, recombination happens and the electron-hole pair is devastated.
Since from the hint, we know that the hole carries a positive charge. So now from the option, we will see the charge on which there will be the positive charge.
Therefore, a proton is the only option which is carrying a positive charge.
Hence, the option $ \left( C \right) $ is correct.
Additional information
Neutrons are particles of a molecule present inside the core of an atom. They have no charge. Protons are decidedly charged particles which are likewise a piece of the nucleus. Electrons are negatively charged particles that rotate around explicit circles (almost certain as the planet spins around the sun).
Note
It's a typical confusion that the P-type and N-type semiconductor is positively and negatively charged, however it isn't. They are neutral as they have the same number of protons and electrons. What the P and N imply is the charge or the expected charge (for p-type of the majority share charge carriers.
Complete step by step answer
At the point when an electron gets energized from the valence band to the conduction band, an opening is made. This is the age of the electron-opening pair. Additionally, when an electron makes a progress from the conduction band to the valence band, recombination happens and the electron-hole pair is devastated.
Since from the hint, we know that the hole carries a positive charge. So now from the option, we will see the charge on which there will be the positive charge.
Therefore, a proton is the only option which is carrying a positive charge.
Hence, the option $ \left( C \right) $ is correct.
Additional information
Neutrons are particles of a molecule present inside the core of an atom. They have no charge. Protons are decidedly charged particles which are likewise a piece of the nucleus. Electrons are negatively charged particles that rotate around explicit circles (almost certain as the planet spins around the sun).
Note
It's a typical confusion that the P-type and N-type semiconductor is positively and negatively charged, however it isn't. They are neutral as they have the same number of protons and electrons. What the P and N imply is the charge or the expected charge (for p-type of the majority share charge carriers.
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