Question

The $ Be{F_2} $ has a:
(A) Linear geometry
(B) Bent geometry
(C) Tetrahedral geometry
(D) Pyramidal geometry
(E) Equilateral triangle geometry

Answer 1

Hint: it is further the fluoride salt of beryllium where beryllium takes the central position and the fluorine occupy the other two.so, the according to the VSEPR theory predicts that $ Be{F_2} $ has a linear geometry with the bond angle $ {180^ \circ } $ .

Complete step by step solution:
Firstly we will try to discuss the geometry of the beryllium difluoride it is further the fluoride salt of beryllium where beryllium takes the central position and the fluorine occupy the other two positions at an angle of $ {180^ \circ } $ from the central atom. further talking about this we come to know that it is an inorganic compound. further it resembles that of the quartz.as a gas it adopts a linear triatomic structure but it is interesting to note here that it shows tetrahedral structure in the liquid form. As according to the VSEPR theory we can discuss the shape of the beryllium difluoride as each of the two valence electrons are shared by the two fluoride atoms.as result of this that the beryllium atom is surrounded by the two bond pairs of electrons. So we can say that the VSEPR theory predicts that $ Be{F_2} $ has a linear geometry with the bond angle $ {180^ \circ } $ .
Further the use of this theory is to know the molecular shapes and the bond angles. Moreover it is important to note here that the shapes of the molecules depend upon repulsion between the bond pair and the lone pair of electrons.
Hence from the above discussion we can conclude that the option A is the correct option for the above question.

Note:
The structure of solid beryllium difluoride resembles that of cristobalite.molecules of liquid beryllium fluoride have a fluctuating tetrahedral structure.additionally the density of liquid $ Be{F_2} $ decreases near its freezing point as the two ions begin to coordinate more strongly with one another leading to the expansion of voids.