
The average age of husband, wife and their child 3 years ago was 27 years and that of wife and the child 5 years ago was 20 years. The present age of husband is:
A.35 years
B.40 years
C.50 years
D.None of these
Answer
561k+ views
Hint: As we know, the average of the ages is the sum of the ages divided by the number of people. In this question, we need to calculate the present age of one person. To calculate this, we will find the sum of 3 person ages 3 years ago and then, sum of 2 person ages 5 years ago. In this way, we can get the sum of their present ages and we can simply subtract them to obtain the present age of one person.
Complete step-by-step answer:
According to the question, the average age of husband, wife and their child 3 years ago was 27 years.
We know, average = sum of their ages / number of persons
Let us assume their present ages:
Present age of the husband is H.
Present age of the wife is W.
Present age of the child is C.
Sum of their present ages $ = H + W + C$
Now, according to the data given in question, for 3 years ago
Sum of their ages will be $\left( {H - 3} \right) + \left( {W - 3} \right) + \left( {C - 3} \right) = H + W + C - 9$
We have average = 27
Using formula for average, we get
\[
A = \dfrac{{H + W + C - 9}}{3} \\
\Rightarrow 27 = \dfrac{{H + W + C - 9}}{3} \\
\Rightarrow 27 \times 3 = H + W + C - 9 \\
\Rightarrow 81 + 9 = H + W + C \\
\Rightarrow 90 = H + W + C \\
\]
So, the sum of their present ages is 90 years.
Now, according to the data given in question, for 5 years ago
Sum of their ages will be $\left( {W - 5} \right) + \left( {C - 5} \right) = W + C - 10$
We have average = 20
Using formula for average, we get
\[
A = \dfrac{{W + C - 10}}{2} \\
\Rightarrow 20 = \dfrac{{W + C - 10}}{2} \\
\Rightarrow 20 \times 2 = W + C - 10 \\
\Rightarrow 40 + 10 = W + C \\
\Rightarrow 50 = W + C \\
\]
So, the sum of wife and child present ages is 50 years.
Now, we need to calculate the present age of the husband.
Present age of husband = sum of husband, wife and child present ages – sum of wife and child present ages
Therefore, present age of husband = 90 – 50 = 40 years
Hence, option B is correct.
Note: Points to remember while solving age problems:-
1.If the present age is y, then n times the present age = ny.
2.If the present age is x, then age n years later/hence = x + n.
3.If the present age is x, then age n years ago = x – n.
4.The ages in a ratio a: b will be ax and bx.
Complete step-by-step answer:
According to the question, the average age of husband, wife and their child 3 years ago was 27 years.
We know, average = sum of their ages / number of persons
Let us assume their present ages:
Present age of the husband is H.
Present age of the wife is W.
Present age of the child is C.
Sum of their present ages $ = H + W + C$
Now, according to the data given in question, for 3 years ago
Sum of their ages will be $\left( {H - 3} \right) + \left( {W - 3} \right) + \left( {C - 3} \right) = H + W + C - 9$
We have average = 27
Using formula for average, we get
\[
A = \dfrac{{H + W + C - 9}}{3} \\
\Rightarrow 27 = \dfrac{{H + W + C - 9}}{3} \\
\Rightarrow 27 \times 3 = H + W + C - 9 \\
\Rightarrow 81 + 9 = H + W + C \\
\Rightarrow 90 = H + W + C \\
\]
So, the sum of their present ages is 90 years.
Now, according to the data given in question, for 5 years ago
Sum of their ages will be $\left( {W - 5} \right) + \left( {C - 5} \right) = W + C - 10$
We have average = 20
Using formula for average, we get
\[
A = \dfrac{{W + C - 10}}{2} \\
\Rightarrow 20 = \dfrac{{W + C - 10}}{2} \\
\Rightarrow 20 \times 2 = W + C - 10 \\
\Rightarrow 40 + 10 = W + C \\
\Rightarrow 50 = W + C \\
\]
So, the sum of wife and child present ages is 50 years.
Now, we need to calculate the present age of the husband.
Present age of husband = sum of husband, wife and child present ages – sum of wife and child present ages
Therefore, present age of husband = 90 – 50 = 40 years
Hence, option B is correct.
Note: Points to remember while solving age problems:-
1.If the present age is y, then n times the present age = ny.
2.If the present age is x, then age n years later/hence = x + n.
3.If the present age is x, then age n years ago = x – n.
4.The ages in a ratio a: b will be ax and bx.
Recently Updated Pages
Master Class 8 Social Science: Engaging Questions & Answers for Success

Master Class 8 Science: Engaging Questions & Answers for Success

Master Class 8 Maths: Engaging Questions & Answers for Success

Class 8 Question and Answer - Your Ultimate Solutions Guide

Full form of MODEM?

What is a numerical label assigned to each device in a network?

Trending doubts
What is BLO What is the full form of BLO class 8 social science CBSE

What is 1 divided by 0 class 8 maths CBSE

In Indian rupees 1 trillion is equal to how many c class 8 maths CBSE

Citizens of India can vote at the age of A 18 years class 8 social science CBSE

Today is Monday After 61 days it will be aWednesda-class-8-maths-CBSE

Write a letter to your class teacher asking for 2 days class 8 english CBSE

