Question

The amount of work done in moving a unit positive charge from infinity to a given point is known as:
A). Nuclear Potential
B). Potential Energy
C). Electric Potential
D). Gravitational Potential

Answer 1

Hint: The given statement is that the amount of the work done in moving a unit positive charge from infinity to a given point. With this statement it is clear that there is charge.
So, charge is in the electrostatic topic.

Complete step by step solution:
So, here are the explanations of the every option
The term nuclear potential, the nuclear potential is demonstrated by the expression for the potential energy of the two nuclei as well as two nucleons is formed.
So, the nuclear potential is the wrong option.
 The term potential energy is that energy which is stored due to its position.
In the term of expression, the potential energy is the product of the mass, acceleration due to gravity, and the height, where we need to calculate the potential energy.
The expression of the potential energy is
$\begin{align}
 & PotentialEnergy = \left( {Mass} \right) \times \left( {acceleration\;due\;to\;gravity} \right) \times (height) \\
  & \left( {P.E.} \right) = \left( {m \times g \times h} \right) \\
\end{align} $
So, the potential energy is the wrong option.
The term electric potential is the amount of work done needed to move the unit of electric charge from a given point to the specific point in the electric field.
The expressions of the electric potential is
$\begin{align}
  &Electric\;Potential = \left[ {\dfrac{{Work\;Done}}{{Electric\;Ch\arg e}}} \right] \\
  &V = \left[ {\dfrac{W}{q}} \right] \\
\end{align} $
So, the electric potential is the right option.
The term gravitational potential, it’s a type of potential energy which is held on by an object because of their height position compared to their lower positions.
In simple words, the energy connects with the gravity or the gravitational force.
The expression of the gravitational potential is
$\begin{align}
& Gravitational\;Potential\;Energy = \left[ {\dfrac{{Gravitational\;Cons\tan t \times mas{s_1} \times mas{s_2}}}{{dis\tan ce}}} \right] \\
  &U = \;\dfrac{{G{m_1}{m_2}}}{r} \\
\end{align} $
So, the gravitational potential is wrong option
So, the option (C) is the correct option

Note: The Potential energy is equal to the work done by the gravitational field moving a body to its given position in the space from infinity. Suppose, there is a body and it has a mass of 1 kilogram, then the potential energy to be allocated to that body is equal to the gravitational potential.