
The ammeter reading in the circuit below is
A. 2 A
B. 3 A
C. 6 A
D. 5 A

Answer
493.5k+ views
Hint: We know that voltage across the parallel circuit remains constant. Use Ohm’s law to express the current through each branch in terms of voltage. Then use KCL to express the sum of currents at any junction in the circuit and substitute the values of current from the concept we discussed earlier.
Formula used:
Ohm’s law,
Here, V is the voltage, I is the current and R is the resistance.
Complete step by step answer:
We assume the current flowing through the first branch is , the current through the second branch is and the current through the third branch is as shown in the figure below.
We know that in the parallel circuit, the voltage across each branch remains the same. Therefore, using Ohm’s law we can write,
We substitute for , for and for in the above equation.
…… (1)
We apply Kirchhoff’s current law at point O as follows,
…… (2)
Using equation (1), we can write the above equation as,
Now, the current flowing through the ammeter is . Therefore, from equation (1), we have,
Therefore, the current through the ammeter is,
So, the correct answer is option (C).
Additional information: Kirchhoff’s voltage current law states that at any junction in the circuit the total incoming current is equal to the total current leaving the junction. The expression of Kirchhoff’s current law can be given as,
Note:
Students should remember that in series circuits, the current remains constant. Therefore, the total current leaves the resistor is equal to total current leaves ammeter. KCL can be applied at any point in the circuit to determine the value of unknown current in the circuit. If we determine the values of current through each branch, the sum of the current should be 11 A.
Formula used:
Ohm’s law,
Here, V is the voltage, I is the current and R is the resistance.
Complete step by step answer:
We assume the current flowing through the first branch is

We know that in the parallel circuit, the voltage across each branch remains the same. Therefore, using Ohm’s law we can write,
We substitute
We apply Kirchhoff’s current law at point O as follows,
Using equation (1), we can write the above equation as,
Now, the current flowing through the ammeter is
Therefore, the current through the ammeter is,
So, the correct answer is option (C).
Additional information: Kirchhoff’s voltage current law states that at any junction in the circuit the total incoming current is equal to the total current leaving the junction. The expression of Kirchhoff’s current law can be given as,
Note:
Students should remember that in series circuits, the current remains constant. Therefore, the total current leaves the resistor
Latest Vedantu courses for you
Grade 10 | CBSE | SCHOOL | English
Vedantu 10 CBSE Pro Course - (2025-26)
School Full course for CBSE students
₹37,300 per year
Recently Updated Pages
Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Biology: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Trending doubts
What is the Full Form of PVC, PET, HDPE, LDPE, PP and PS ?

Why should a magnesium ribbon be cleaned before burning class 12 chemistry CBSE

A renewable exhaustible natural resources is A Coal class 12 biology CBSE

Megasporangium is equivalent to a Embryo sac b Fruit class 12 biology CBSE

What is Zeises salt and ferrocene Explain with str class 12 chemistry CBSE

How to calculate power in series and parallel circ class 12 physics CBSE
