Question

What is the sum of all the angles of a Hexagon?

Answer 1

Hint: The word “Polygon” is the combination of two words, i.e. “poly” (means many) and “gon” (means sides). We need to find the sum of all angles of a Hexagon. We know that, sum of all angles of a $n$ sided polygon is $$(n-2)\times {180}^{\circ }$$. Here, we know that a Hexagon has 6 sides. So substitute this value of $n$ in the formula to get the final output. Or we can divide the hexagon in triangles such that no triangles overlap each other. Since, we know that, the sum of the interior angles of the triangle is $${180}^{\circ }$$.

Complete step-by-step answer:
We know that,
A hexagon is a polygon with six sides.
An interior angle is an angle measured between the two sides of a polygon.
The sum of the interior angles of a hexagon can be calculated in two ways:
1) Dividing hexagon into triangles
2) Interior angle sum formula

First, We are going to divide the Hexagon into four triangles as shown below:

The given Hexagon is divided into 4 triangles (do not overlap) namely,
$$\mathrm{\Delta }BCA,\mathrm{\Delta }CDA,\mathrm{\Delta }DEA,\mathrm{\Delta }EFA$$
So, the sum of the angles (interior) is
$$=\mathrm{\angle }A+\mathrm{\angle }B+\mathrm{\angle }C+\mathrm{\angle }D+\mathrm{\angle }E+\mathrm{\angle }F$$
$$=\left(\mathrm{\angle }BAC+\mathrm{\angle }CAD+\mathrm{\angle }DAE+\mathrm{\angle }FAE\right)+\mathrm{\angle }B+\left(\mathrm{\angle }BCA+\mathrm{\angle }DCA\right)+\left(\mathrm{\angle }CDA+\mathrm{\angle }EDA\right)+\left(\mathrm{\angle }AEF+\mathrm{\angle }AED\right)+\mathrm{\angle }F$$Rearranging the terms, we will get,
$$=\left(\mathrm{\angle }BAC+\mathrm{\angle }B+\mathrm{\angle }BCA\right)+\left(\mathrm{\angle }CAD+\mathrm{\angle }DCA+\mathrm{\angle }CDA\right)+\left(\mathrm{\angle }EDA+\mathrm{\angle }DAE+\mathrm{\angle }AED\right)+\left(\mathrm{\angle }AEF+\mathrm{\angle }FAE+\mathrm{\angle }F\right)$$
=Sum of the interior angle of $$\mathrm{\Delta }BCA$$ + Sum of the interior angles of $$\mathrm{\Delta }CDA$$ + Sum of the interior angles of $$\mathrm{\Delta }DEA$$ + Sum of the interior angles of $$\mathrm{\Delta }EFA$$.
Since, the sum of the interior angles of the triangle is $${180}^{\circ }$$.
$$={180}^{\circ }+{180}^{\circ }+{180}^{\circ }+{180}^{\circ }$$
$$={720}^{\circ }$$
Therefore, the sum of the angles of a hexagon is $${720}^{\circ }$$.

Note:
Method 2: Using interior angle sum formula:
We know that,
Sum of the interior angles of a n-gon is
$$=(n-2)\times {180}^{\circ }$$ where n means number of sides.
For a hexagon, n = 6.
So, substituting this value of n in the above formula, we will get,
$$=(6-2)\times {180}^{\circ }$$
Simply this, we will get,
$$=4\times {180}^{\circ }$$
$$={720}^{\circ }$$
Hence, the sum of the angles of a hexagon is $${720}^{\circ }$$.
For irregular hexagons also, it is true.

Method 3:
The sum of the interior angles of a hexagon = 4 times the sum of the interior angles of a triangle
$$=4\times {180}^{\circ }$$
$$={720}^{\circ }$$
So, the correct answer is “$${720}^{\circ }$$”.

A polygon is a two-dimensional geometric figure that has a finite number of sides. The sides of a polygon are made of straight line segments connected to each other end to end. A circle is also a plane figure but it is not considered as a polygon, because it is a curved shape and does not have sides or angles. A minimum of three line segments is required to connect end to end, to make a closed figure. Thus a polygon with a minimum of three sides is known as Triangle and it is also called 3-gon. An n-sided polygon is called n-gon.