State whether True or False: If a number is divisible by \[9\], it must be divisible by \[3\] A. True B. False
Hint: Here we use the concept that any number \[a\] when divided by \[b\] can be written as \[a = bq + r\] where \[q\] is the quotient and \[r\] is the remainder. A number is completely divisible by any number if its remainder is zero i.e. it can be written in the form \[a = bq\]. So we write number divisible by \[9\] then further factoring nine we write if the number is divisible by factors of \[9\]
Complete step-by-step answer: General equation of a number \[a\] completely divisible by \[b\] is \[a = bq\]. Since, we are given a number is divisible by \[9\], so put the value \[b = 9\] in the above equation. We can write \[a = 9q\] Since, we can write nine in simpler form i.e. \[9 = 3 \times 3\] Therefore, we can write \[a = 9q = (3 \times 3)q\] Group together all the factors other than \[3\] \[a = 3 \times (3q)\] Assuming the factor \[3q = p\] We can write \[a = 3p\] which is of the form \[a = bq\], where \[b = 3\] Therefore, number \[a\] is divisible by \[3\] Since, the number on the LHS of the equation is the same, we can say the number that is divisible by \[9\] is also divisible by \[3\] . So, the statement in the question is true.
So, the correct answer is “Option A”.
Note: Students many times make mistake when they assume looking at the word divisible by a number and they write the number in fraction form which is wrong, keep in mind that whenever a number is divisible by another number then the first number can be written as a multiple of second number. Alternate method: We can also show this solution by taking an example Say a number is divisible by \[9\], let us take that number to be \[36\] We can write \[36 = 9 \times 4\] Since we know \[9 = 3 \times 3\] Therefore, we can write \[36 = 3 \times 3 \times 4\] Grouping together all factors other than three \[ 36 = 3 \times (3 \times 4) \\ 36 = 3 \times 12 \\ \] Therefore, the number is divisible by \[3\] as it is written in the form of multiple of three.
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