State Kirchhoff’s voltage law.
Answer
599.7k+ views
Hint: Here, in the question, we need to define and explain the Kirchhoff’s law. Kirchhoff’s law is divided into two sub-parts, i.e., Kirchhoff’s current law and Kirchhoff’s voltage law. We will limit our discussion here to Kirchhoff's voltage law only.
Complete step by step answer:
According to Kirchhoff’s voltage law, the algebraic sum of the voltage drop across all the elements in a closed circuit equals to zero. In other words, Kirchhoff's law is the conservation of energy in a closed circuit. Mathematically $\sum V = 0$.
Let us take an example to better understand the topic.
Consider a closed circuit such that a resistor of resistance R, an inductor of inductance L, and a capacitor of capacitance C are connected in series across an AC voltage source, V. Also, consider a current I flowing in the closed circuit.
In the shown figure, let us apply the Kirchhoff’s voltage rule as:
$
V - {V_R} - {V_L} - {V_C} = 0 \\
\Rightarrow V - IR - L\dfrac{{dI}}{{dt}} - \dfrac{1}{C}\int {Idt} = 0 \\
\Rightarrow V = IR + L\dfrac{{dI}}{{dt}} + \dfrac{1}{C}\int {Idt} \\
$
Hence, we can see that the energy remains conserved in the given circuit.
Note:
It is interesting to note here that the full name of Kirchhoff’s voltage law is Gustav Kirchhoff’s Voltage Law, in which Gustav Kirchhoff is the name of the scientist who discovered this law. Moreover, it is advised to the students to be aware while using the current sign convention and it varies from person-to-person.
Complete step by step answer:
According to Kirchhoff’s voltage law, the algebraic sum of the voltage drop across all the elements in a closed circuit equals to zero. In other words, Kirchhoff's law is the conservation of energy in a closed circuit. Mathematically $\sum V = 0$.
Let us take an example to better understand the topic.
Consider a closed circuit such that a resistor of resistance R, an inductor of inductance L, and a capacitor of capacitance C are connected in series across an AC voltage source, V. Also, consider a current I flowing in the closed circuit.
In the shown figure, let us apply the Kirchhoff’s voltage rule as:
$
V - {V_R} - {V_L} - {V_C} = 0 \\
\Rightarrow V - IR - L\dfrac{{dI}}{{dt}} - \dfrac{1}{C}\int {Idt} = 0 \\
\Rightarrow V = IR + L\dfrac{{dI}}{{dt}} + \dfrac{1}{C}\int {Idt} \\
$
Hence, we can see that the energy remains conserved in the given circuit.
Note:
It is interesting to note here that the full name of Kirchhoff’s voltage law is Gustav Kirchhoff’s Voltage Law, in which Gustav Kirchhoff is the name of the scientist who discovered this law. Moreover, it is advised to the students to be aware while using the current sign convention and it varies from person-to-person.
Recently Updated Pages
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Trending doubts
Which are the Top 10 Largest Countries of the World?

Draw a labelled sketch of the human eye class 12 physics CBSE

Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE

What are the major means of transport Explain each class 12 social science CBSE

Sulphuric acid is known as the king of acids State class 12 chemistry CBSE

Why should a magnesium ribbon be cleaned before burning class 12 chemistry CBSE

