
State how magnetic susceptibility is different for the three types of magnetic materials, i.e.; diamagnetic, paramagnetic and ferromagnetic materials
Answer
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Hint: The magnetic materials get magnetized when we apply a magnetic field. The magnetic susceptibility will measure how much the magnet gets magnetized. It varies with different magnetic materials.
Formula used:
The formula which shows the relation between the magnetic susceptibility and magnetic intensity is given by,
$M = \chi H$
Where, $M$ is the magnetization, $\chi $ is the magnetic susceptibility and $H$ is the magnetic intensity.
Complete Answer:
Let’s know about the diamagnetic materials. There is no atomic dipole present in these materials. This is because the electrons are paired. And the resultant magnetic moment of diamagnetic material is zero. The diamagnetic materials can be easily magnetized when we are placing them in the magnetic field. And the magnetic materials will align against the direction of the applied magnetic field. The magnetic susceptibility will be a negative value.
And let’s know about the paramagnetic materials. The atomic dipole is present here. It is due to the unpaired electrons. And the net dipole moment of all the material in the paramagnet will not add up to zero. When the magnetic field is applied the paramagnetic materials will align partially only. Thus, the magnetic susceptibility will be positive. They are not much larger in value.
And the ferromagnetic materials are highly magnetic materials. Even when they are not magnetized the atomic dipoles are aligned. When the external magnetic field is applied, the magnetic particles aligned in the direction of the applied magnetic field. The magnetic susceptibility will be a larger positive value.
Note: The material having higher magnetic susceptibility will be having more magnetic strength. Hence the ferromagnetic materials have greater magnetic property. By assuming the magnetization is constant, then the magnetic susceptibility and the magnetic intensity are inversely proportional.
Formula used:
The formula which shows the relation between the magnetic susceptibility and magnetic intensity is given by,
$M = \chi H$
Where, $M$ is the magnetization, $\chi $ is the magnetic susceptibility and $H$ is the magnetic intensity.
Complete Answer:
Let’s know about the diamagnetic materials. There is no atomic dipole present in these materials. This is because the electrons are paired. And the resultant magnetic moment of diamagnetic material is zero. The diamagnetic materials can be easily magnetized when we are placing them in the magnetic field. And the magnetic materials will align against the direction of the applied magnetic field. The magnetic susceptibility will be a negative value.
And let’s know about the paramagnetic materials. The atomic dipole is present here. It is due to the unpaired electrons. And the net dipole moment of all the material in the paramagnet will not add up to zero. When the magnetic field is applied the paramagnetic materials will align partially only. Thus, the magnetic susceptibility will be positive. They are not much larger in value.
And the ferromagnetic materials are highly magnetic materials. Even when they are not magnetized the atomic dipoles are aligned. When the external magnetic field is applied, the magnetic particles aligned in the direction of the applied magnetic field. The magnetic susceptibility will be a larger positive value.
Note: The material having higher magnetic susceptibility will be having more magnetic strength. Hence the ferromagnetic materials have greater magnetic property. By assuming the magnetization is constant, then the magnetic susceptibility and the magnetic intensity are inversely proportional.
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