Question & Answer
QUESTION

\[\sqrt 2 \]is a polynomial of degree

ANSWER
\[\sqrt 2 \] is a constant polynomial. The only term here is\[\sqrt 2 \] which can be written as\[\sqrt 2 {x^0}\].
So, the exponent of x is zero. Therefore, the degree of the polynomial is 0.
Hence, (b) is the correct answer.