
Southee purchased $\text{8 kg 428 g}$ of grain and Miln purchased $\text{4 kg 634 g}$ more grain than purchased by Southee. What quantity of grain did Southee and Miln purchase?
Answer
413.7k+ views
Hint: To solve this question we need to have the knowledge of arithmetic operations. We should know about the units also. To solve this we will be adding the weight of grains purchased by Southee and Miln. Weight of grain purchased by Miln will be the sum of grain purchased by Southee and the extra grain. Then we will be adding the total grain purchased by them.
Complete step by step answer:
The question ask us to find the value of the total amount of grains which will be purchased by Southee and Miln when Southee purchased $\text{8 kg 428 g}$ of grain and Miln purchased $\text{4 kg 634 g}$ more grain that purchased by Southee. The first step is to calculate the amount of grain Miln purchased. Weight of grain Miln purchased will be the sum of grain purchased by Southee and the extra amount. On writing it mathematically we get:
Amount of grain Miln purchased = Amount of grain Southee purchased +$\text{4 kg 634 g}$
Amount of grain Southee purchased is given as $\text{8 kg 428 g}$. On substituting the weight we get:
Amount of grain Miln purchased = $\text{8 kg 428 g}$+$\text{4 kg 634 g}$
To add dimension of different units we add the values of the same unit, which means kg will be added to kg and gram to gram.
Amount of grain Miln purchased = $\text{13 kg 062 g}$
Now we will find the amount of grains purchased by both Southee and Miln. For this we will add the amount purchased by Southee to the amount of grain purchased by Miln. On calculating we get:
Total grain purchased = Amount of grain Miln purchased + Amount of grain Southee purchased
On substituting the values of the weight we get:
Total grain purchased = $\text{13 kg 062 g +8 kg 428 g}$
Total grain purchased = $\text{21 kg 490 g }$
$\therefore $ Total amount of grain that Southee and Miln purchased is $\text{21 kg 490 g }$.
Note: To solve these types of questions the units should be the same for any algebraic operation to take place. Always remember that we need to convert the unit into the same unit for the correct answer. The above weight could also be added as decimal numbers. For example $\text{8 kg 428 g}$could be written as $\text{8}\text{.428 kg}$.
Complete step by step answer:
The question ask us to find the value of the total amount of grains which will be purchased by Southee and Miln when Southee purchased $\text{8 kg 428 g}$ of grain and Miln purchased $\text{4 kg 634 g}$ more grain that purchased by Southee. The first step is to calculate the amount of grain Miln purchased. Weight of grain Miln purchased will be the sum of grain purchased by Southee and the extra amount. On writing it mathematically we get:
Amount of grain Miln purchased = Amount of grain Southee purchased +$\text{4 kg 634 g}$
Amount of grain Southee purchased is given as $\text{8 kg 428 g}$. On substituting the weight we get:
Amount of grain Miln purchased = $\text{8 kg 428 g}$+$\text{4 kg 634 g}$
To add dimension of different units we add the values of the same unit, which means kg will be added to kg and gram to gram.
Amount of grain Miln purchased = $\text{13 kg 062 g}$
Now we will find the amount of grains purchased by both Southee and Miln. For this we will add the amount purchased by Southee to the amount of grain purchased by Miln. On calculating we get:
Total grain purchased = Amount of grain Miln purchased + Amount of grain Southee purchased
On substituting the values of the weight we get:
Total grain purchased = $\text{13 kg 062 g +8 kg 428 g}$
Total grain purchased = $\text{21 kg 490 g }$
$\therefore $ Total amount of grain that Southee and Miln purchased is $\text{21 kg 490 g }$.
Note: To solve these types of questions the units should be the same for any algebraic operation to take place. Always remember that we need to convert the unit into the same unit for the correct answer. The above weight could also be added as decimal numbers. For example $\text{8 kg 428 g}$could be written as $\text{8}\text{.428 kg}$.
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