
How do you solve the following system $ y = 4x - 13,y - 3x = - 2 $ ?
Answer
548.4k+ views
Hint: In order to determine the solution of a given system of equations having two variables, use the method of elimination of term by eliminating the $ y $ term by making the mod of coefficient of $ y $ in both the equations equal. Then apply the operation of addition or subtraction between the equation to eliminate $ y $ term. Solve the result for $ x $ and put the obtained value of $ x $ in any of the equations given to get the value of $ x $.
Complete step by step solution:
We are given pair of linear equation in two variables \[y = 4x - 13,y - 3x = - 2\]
$ y = 4x - 13 $ ---(1)
\[y - 3x = - 2\]
Rewriting the above by transposing term containing $ x $ toward right-hand side
\[y = 3x - 2\]----(2)
In order to solve the system of equations, we have many methods like, substitution, elimination of term, and cross-multiplication.
Here we will be using an elimination method to eliminate the term having $ y $ from both the equations.
And to do so we have to first make the mod of coefficient of $ y $ in both the equation equal to each.
As we can clearly see that the mod of coefficient of $ y $ in both the equations are already equal.
Now subtracting both the equation, we get
$
\Rightarrow y - y = 4x - 13 - \left( {3x - 2} \right) \\
0 = 4x - 13 - 3x + 2 \;
$
Combining like terms we get
$ x - 11 = 0 $
Solving the equation for variable $ x $
$ x = 11 $
Hence, we have obtained the value of $ x = 11 $ .
Now putting this value of $ x $ in the equation (2) to get the value of \[y\]
\[
\Rightarrow y = 3\left( {11} \right) - 2 \\
y = 33 - 2 \\
y = 31 \;
\]
Therefore, the solution of system of given equations is $ x = 11,y = 31 $
So, the correct answer is “ $ x = 11,y = 31 $ ”.
Note: Linear Equation in two variable: A linear equation is a equation which can be represented in the form of $ ax + by + c $ where $ x $ and $ y $ are the unknown variables and c is the number known where $ a \ne 0,b \ne 0 $ .
The degree of the variable in the linear equation is of the order 1.One must be careful while calculating the answer as calculation error may come.
Complete step by step solution:
We are given pair of linear equation in two variables \[y = 4x - 13,y - 3x = - 2\]
$ y = 4x - 13 $ ---(1)
\[y - 3x = - 2\]
Rewriting the above by transposing term containing $ x $ toward right-hand side
\[y = 3x - 2\]----(2)
In order to solve the system of equations, we have many methods like, substitution, elimination of term, and cross-multiplication.
Here we will be using an elimination method to eliminate the term having $ y $ from both the equations.
And to do so we have to first make the mod of coefficient of $ y $ in both the equation equal to each.
As we can clearly see that the mod of coefficient of $ y $ in both the equations are already equal.
Now subtracting both the equation, we get
$
\Rightarrow y - y = 4x - 13 - \left( {3x - 2} \right) \\
0 = 4x - 13 - 3x + 2 \;
$
Combining like terms we get
$ x - 11 = 0 $
Solving the equation for variable $ x $
$ x = 11 $
Hence, we have obtained the value of $ x = 11 $ .
Now putting this value of $ x $ in the equation (2) to get the value of \[y\]
\[
\Rightarrow y = 3\left( {11} \right) - 2 \\
y = 33 - 2 \\
y = 31 \;
\]
Therefore, the solution of system of given equations is $ x = 11,y = 31 $
So, the correct answer is “ $ x = 11,y = 31 $ ”.
Note: Linear Equation in two variable: A linear equation is a equation which can be represented in the form of $ ax + by + c $ where $ x $ and $ y $ are the unknown variables and c is the number known where $ a \ne 0,b \ne 0 $ .
The degree of the variable in the linear equation is of the order 1.One must be careful while calculating the answer as calculation error may come.
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