
Solve the following expression, ${{\left( 205 \right)}^{2}}-{{\left( 195 \right)}^{2}}$.
Answer
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Hint: We are given an expression of the form ${{a}^{2}}-{{b}^{2}}$. So, we can solve this by using ${{a}^{2}}-{{b}^{2}}=\left( a+b \right)\left( a-b \right)$ by taking a = 205 and b = 195 and then solve it to get the value of ${{\left( 205 \right)}^{2}}-{{\left( 195 \right)}^{2}}$.
Complete step-by-step solution
In this question, we have been asked to find the value of the expression, ${{\left( 205 \right)}^{2}}-{{\left( 195 \right)}^{2}}$. Let us consider the expression given in the question as follows.
$\Rightarrow E={{\left( 205 \right)}^{2}}-{{\left( 195 \right)}^{2}}.........\left( i \right)$
Let 205 = a and 195 = b. By substituting these value in equation (i), we will get,
$\Rightarrow E={{a}^{2}}-{{b}^{2}}$
By adding and subtracting the term (ab) on the RHS of the above equation, we will get,
$\Rightarrow E={{a}^{2}}-{{b}^{2}}+ab-ab$
By grouping the terms of the above equation, we will get,
$\Rightarrow E=\left( {{a}^{2}}+ab \right)-\left( {{b}^{2}}+ab \right)$
Now, by taking out the common terms from each group we will get,
$\Rightarrow E=a\left( a+b \right)-b\left( a+b \right)$
By taking out the term (a + b) common from both the terms, we get,
$\Rightarrow E=\left( a+b \right)\left( a-b \right)$
Now, by again substituting a = 205 and b = 195 that we had assumed earlier, in the above equation, we will get,
$\begin{align}
&\Rightarrow E=\left( 205+195 \right)\left( 205-195 \right) \\
&\Rightarrow E=\left( 400 \right)\times \left( 10 \right) \\
&\Rightarrow E=4000 \\
\end{align}$
Therefore, we get the value of the expression, that is, ${{\left( 205 \right)}^{2}}-{{\left( 195 \right)}^{2}}$ as 4000.
Note: In this question, the students must remember that any expression of the form ${{a}^{2}}-{{b}^{2}}$ is solved by writing it as $\left( a+b \right)\left( a-b \right)$. In this question, some students may find ${{\left( 205 \right)}^{2}}$ and ${{\left( 195 \right)}^{2}}$ separately and then solve the question as follows:
$\begin{align}
&\Rightarrow E={{\left( 205 \right)}^{2}}-{{\left( 195 \right)}^{2}} \\
&\Rightarrow E=42025-38025 \\
&\Rightarrow E=4000 \\
\end{align}$
From this also, we get ${{\left( 205 \right)}^{2}}-{{\left( 195 \right)}^{2}}=4000$. Though this method is also correct, it is very time consuming because of the multiplication of 3 digit numbers. And also it can lead to calculation mistakes which results in the wrong answer. So, the students must choose the method accordingly and then solve the question correctly.
Complete step-by-step solution
In this question, we have been asked to find the value of the expression, ${{\left( 205 \right)}^{2}}-{{\left( 195 \right)}^{2}}$. Let us consider the expression given in the question as follows.
$\Rightarrow E={{\left( 205 \right)}^{2}}-{{\left( 195 \right)}^{2}}.........\left( i \right)$
Let 205 = a and 195 = b. By substituting these value in equation (i), we will get,
$\Rightarrow E={{a}^{2}}-{{b}^{2}}$
By adding and subtracting the term (ab) on the RHS of the above equation, we will get,
$\Rightarrow E={{a}^{2}}-{{b}^{2}}+ab-ab$
By grouping the terms of the above equation, we will get,
$\Rightarrow E=\left( {{a}^{2}}+ab \right)-\left( {{b}^{2}}+ab \right)$
Now, by taking out the common terms from each group we will get,
$\Rightarrow E=a\left( a+b \right)-b\left( a+b \right)$
By taking out the term (a + b) common from both the terms, we get,
$\Rightarrow E=\left( a+b \right)\left( a-b \right)$
Now, by again substituting a = 205 and b = 195 that we had assumed earlier, in the above equation, we will get,
$\begin{align}
&\Rightarrow E=\left( 205+195 \right)\left( 205-195 \right) \\
&\Rightarrow E=\left( 400 \right)\times \left( 10 \right) \\
&\Rightarrow E=4000 \\
\end{align}$
Therefore, we get the value of the expression, that is, ${{\left( 205 \right)}^{2}}-{{\left( 195 \right)}^{2}}$ as 4000.
Note: In this question, the students must remember that any expression of the form ${{a}^{2}}-{{b}^{2}}$ is solved by writing it as $\left( a+b \right)\left( a-b \right)$. In this question, some students may find ${{\left( 205 \right)}^{2}}$ and ${{\left( 195 \right)}^{2}}$ separately and then solve the question as follows:
$\begin{align}
&\Rightarrow E={{\left( 205 \right)}^{2}}-{{\left( 195 \right)}^{2}} \\
&\Rightarrow E=42025-38025 \\
&\Rightarrow E=4000 \\
\end{align}$
From this also, we get ${{\left( 205 \right)}^{2}}-{{\left( 195 \right)}^{2}}=4000$. Though this method is also correct, it is very time consuming because of the multiplication of 3 digit numbers. And also it can lead to calculation mistakes which results in the wrong answer. So, the students must choose the method accordingly and then solve the question correctly.
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