Solve the following expression : \[{11^3} + {12^3} + ... + {20^3}\]
A. Cannot be determined
B. is divisible by $5$ having negative sign
C. is divisible by \[10\]
D. is divisible by $5$
Answer
524.4k+ views
Hint: In the given problem, we need to find the sum of the given sequential series which involves some certain algebraic parameters such as cubes. So, to solve the desired expression, we will consider the formula for summation of the cubes of the first ‘n’ natural numbers ‘N’ (by considering the previous series of the given sequence) respectively.
Complete step by step answer:
The given expression implies sequential series,
\[{11^3} + {12^3} + ... + {20^3}\]
As a result, the series is the series containing the addition having cube of each term,
Since, we know that the sum of such cases are,
${S_n} = \dfrac{{n{{\left( {n + 1} \right)}^2}}}{2}$
where, ‘${S_n}$’ is the sum of the respective series, and ‘$n$’ is the last term in the respective series.
Now, considering the expression \[{11^3} + {12^3} + ... + {20^3}\]. But, the expression or sequence or series, is incomplete, hence, considering the similar previous series that is \[{1^3} + {2^3} + ... + {10^3}\], we get
\[{S_n} = \left( {{{11}^3} + {{12}^3} + ... + {{20}^3}} \right) - \left( {{1^3} + {2^3} + ... + {{10}^3}} \right)\]
Now, using the formula mentioned above
${S_n} = \dfrac{{n{{\left( {n + 1} \right)}^2}}}{2}$
We get
\[{S_n} = \dfrac{{20{{\left( {20 + 1} \right)}^2}}}{2} - \dfrac{{10{{\left( {10 + 1} \right)}^2}}}{2}\]
Solving the equation mathematically, we get
\[{S_n} = \dfrac{{20{{\left( {21} \right)}^2}}}{2} - \dfrac{{10{{\left( {11} \right)}^2}}}{2} \\
\Rightarrow {S_n} = \dfrac{{20\left( {441} \right)}}{2} - \dfrac{{10\left( {121} \right)}}{2} \\ \]
Hence, the required sum of the series is,
\[{S_n} = \dfrac{{8820}}{2} - \dfrac{{1210}}{2} \\
\Rightarrow {S_n} = \dfrac{{7610}}{2} \\
\therefore {S_n} = 3805 \]
As a result, it seems that the sum of the given series is divisible by $5$ that is ${S_n} = \dfrac{{3805}}{5} = 761$ where the remainder is ‘zero’!
Hence, option D is correct.
Note: For finding the certain sum of the sequential series problem algebraically, consider the previous term or a series\[{1^3} + {2^3} + ... + {10^3}\]for this problem particularly. As a result, to that term we have the generalized formula for the summation of cubes i.e.${S_n} = \dfrac{{n{{\left( {n + 1} \right)}^2}}}{2}$respectively. Learning these equations or formulae will be really helpful to solve these drastic problems as per sequential series is concerned. Care should be taken while solving the certain equations.
Complete step by step answer:
The given expression implies sequential series,
\[{11^3} + {12^3} + ... + {20^3}\]
As a result, the series is the series containing the addition having cube of each term,
Since, we know that the sum of such cases are,
${S_n} = \dfrac{{n{{\left( {n + 1} \right)}^2}}}{2}$
where, ‘${S_n}$’ is the sum of the respective series, and ‘$n$’ is the last term in the respective series.
Now, considering the expression \[{11^3} + {12^3} + ... + {20^3}\]. But, the expression or sequence or series, is incomplete, hence, considering the similar previous series that is \[{1^3} + {2^3} + ... + {10^3}\], we get
\[{S_n} = \left( {{{11}^3} + {{12}^3} + ... + {{20}^3}} \right) - \left( {{1^3} + {2^3} + ... + {{10}^3}} \right)\]
Now, using the formula mentioned above
${S_n} = \dfrac{{n{{\left( {n + 1} \right)}^2}}}{2}$
We get
\[{S_n} = \dfrac{{20{{\left( {20 + 1} \right)}^2}}}{2} - \dfrac{{10{{\left( {10 + 1} \right)}^2}}}{2}\]
Solving the equation mathematically, we get
\[{S_n} = \dfrac{{20{{\left( {21} \right)}^2}}}{2} - \dfrac{{10{{\left( {11} \right)}^2}}}{2} \\
\Rightarrow {S_n} = \dfrac{{20\left( {441} \right)}}{2} - \dfrac{{10\left( {121} \right)}}{2} \\ \]
Hence, the required sum of the series is,
\[{S_n} = \dfrac{{8820}}{2} - \dfrac{{1210}}{2} \\
\Rightarrow {S_n} = \dfrac{{7610}}{2} \\
\therefore {S_n} = 3805 \]
As a result, it seems that the sum of the given series is divisible by $5$ that is ${S_n} = \dfrac{{3805}}{5} = 761$ where the remainder is ‘zero’!
Hence, option D is correct.
Note: For finding the certain sum of the sequential series problem algebraically, consider the previous term or a series\[{1^3} + {2^3} + ... + {10^3}\]for this problem particularly. As a result, to that term we have the generalized formula for the summation of cubes i.e.${S_n} = \dfrac{{n{{\left( {n + 1} \right)}^2}}}{2}$respectively. Learning these equations or formulae will be really helpful to solve these drastic problems as per sequential series is concerned. Care should be taken while solving the certain equations.
Recently Updated Pages
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

State and prove Bernoullis theorem class 11 physics CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

