Answer
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Hint: Take the like terms that are terms with same variables to one side of the equation and rest others to the other side of the equation. Then perform necessary simplification to get the value of x.
Complete step-by-step answer:
Given equation is
$3x + 2 = 50 - x$
Now shift the variable x to L.H.S and constant term 2 to R.H.S
$ \Rightarrow 3x + x = 50 - 2$
Now simplify the above equation we have,
$ \Rightarrow 4x = 48$
Now dive by 4 throughout we have,
$ \Rightarrow \dfrac{{4x}}{4} = \dfrac{{48}}{4}$
Now cancel out 4 from numerator and denominator from the L.H.S we have,
$ \Rightarrow x = \dfrac{{48}}{4} = 12$
So 12 is the required solution of the given equation.
Note: Whenever we face problems of such kind the key concept is to simplify the like terms by carefully performing arithmetic operation on the coefficients. This will help to minimize the chances of making any silly errors while solving for the value of any unknown.
Complete step-by-step answer:
Given equation is
$3x + 2 = 50 - x$
Now shift the variable x to L.H.S and constant term 2 to R.H.S
$ \Rightarrow 3x + x = 50 - 2$
Now simplify the above equation we have,
$ \Rightarrow 4x = 48$
Now dive by 4 throughout we have,
$ \Rightarrow \dfrac{{4x}}{4} = \dfrac{{48}}{4}$
Now cancel out 4 from numerator and denominator from the L.H.S we have,
$ \Rightarrow x = \dfrac{{48}}{4} = 12$
So 12 is the required solution of the given equation.
Note: Whenever we face problems of such kind the key concept is to simplify the like terms by carefully performing arithmetic operation on the coefficients. This will help to minimize the chances of making any silly errors while solving for the value of any unknown.
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