
How do you solve \[\tan \left( {38} \right) = \dfrac{x}{{12}}\]?
Answer
555.9k+ views
Hint: In the given question, we have been given a linear equation in one variable. We have to solve for the value of the given variable. We can easily do that if we know the method to solve any linear equation in one variable. We can do that by taking the constant multiplied with the variable to the other side, so as to free the variable of any coefficient and then simplify the constants to get the value of the variable.
Formula Used:
We are going to use the formula of linear equation,
If \[\dfrac{x}{a} = b\]
then \[x = a \times b\]
Complete step by step answer:
The equation to be solved is \[\tan \left( {38} \right) = \dfrac{x}{{12}}\].
We just take the \[12\] being divided with \[x\] to the other side, and when taken to other side, it is going to multiply the term \[\left( {\tan \left( {38} \right)} \right)\] on that side.
Hence, \[x = \tan \left( {38} \right) \times 12\]
Now, \[\tan \left( {38} \right) \approx 0.7813\]
Thus, \[x = 12 \times 0.7813 = 9.375\]
Note:
In the given question, we had to calculate the value of a linear equation in one variable. We did that by taking the constant dividing the variable to the other side containing the other constant. Then we simply multiplied the constants and got our answer.
Formula Used:
We are going to use the formula of linear equation,
If \[\dfrac{x}{a} = b\]
then \[x = a \times b\]
Complete step by step answer:
The equation to be solved is \[\tan \left( {38} \right) = \dfrac{x}{{12}}\].
We just take the \[12\] being divided with \[x\] to the other side, and when taken to other side, it is going to multiply the term \[\left( {\tan \left( {38} \right)} \right)\] on that side.
Hence, \[x = \tan \left( {38} \right) \times 12\]
Now, \[\tan \left( {38} \right) \approx 0.7813\]
Thus, \[x = 12 \times 0.7813 = 9.375\]
Note:
In the given question, we had to calculate the value of a linear equation in one variable. We did that by taking the constant dividing the variable to the other side containing the other constant. Then we simply multiplied the constants and got our answer.
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