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Solve: $\dfrac{3y-2}{2y+4}=\dfrac{7}{6}$.

Answer
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606.9k+ views
Hint: We will first start by cross multiplying the equation. Then we will collect the similar terms and perform addition. Then we will further simplify the equation to further simplify the equation and find the value of x.

Complete step-by-step answer:
Now, we have been given that $\dfrac{3y-2}{2y+4}=\dfrac{7}{6}$.
Now, we will cross – multiply the equation. So, we have the equation as,
\[\begin{align}
  & 6\left( 3y-2 \right)=7\left( 2y+4 \right) \\
 & 18y-12=14y+28 \\
\end{align}\]
Now, we will collect the terms with y on one side and the constant terms on the other. So, we have,
$\begin{align}
  & 18y-14y=12+28 \\
 & 4y=40 \\
 & y=10 \\
\end{align}$
So, the value of y is 10.

Note: It is important to note that we have first collected the similar terms on one side and then add them to find the value of variable y by doing this. We separate the variables and hence, it becomes easier to find the value of the variable.

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