
How do you solve $3\left( {4 - 8b} \right) - 3\left( {4b + 6} \right) = - 6$?
Answer
545.1k+ views
Hint: First step is to apply distributivity property in the given equation, i.e., multiplying each addend individually by the number and then adding the products together. Next, we have to isolate the variable terms on one side by performing the same mathematical operations on both sides of the equation. Next step is to isolate the constant terms on the other side by performing the same mathematical operations on both sides of the equation. Next step is to make the coefficient of the variable equal to $1$ using multiplication or division property.
Complete step by step solution:
Given an algebraic equation is $3\left( {4 - 8b} \right) - 3\left( {4b + 6} \right) = - 6$.
We have to find the value of $b$.
First, we have to apply the distributive property in the given equation, i.e., multiplying each addend individually by the number and then adding the products together.
$3 \cdot 4 + 3\left( { - 8b} \right) - 3\left( {4b} \right) - 3 \cdot 6 = - 6$
Calculate the product of each term in the left hand side of the equation.
$ \Rightarrow 12 - 24b - 12b - 18 = - 6$
Add variables terms and constant terms in the left hand side of the equation.
$ \Rightarrow - 36b - 6 = - 6$
Now we have to isolate the variable terms on one side by performing the same mathematical operations on both sides of the equation.
So, adding $6$ to both sides of the equation, we get
$ \Rightarrow - 36b - 6 + 6 = - 6 + 6$
$ \Rightarrow - 36b = 0$
Now we have to make the coefficient of the variable equal to $1$ using multiplication or division property.
So, dividing both sides of the equation by $ - 36$, we get
\[ \Rightarrow \dfrac{{ - 36b}}{{ - 36}} = \dfrac{0}{{ - 36}}\]
$\therefore b = 0$
Final solution: Therefore, $b = 0$ is the solution of $3\left( {4 - 8b} \right) - 3\left( {4b + 6} \right) = - 6$.
Note:
An algebraic equation is an equation involving variables. It has an equality sign. The expression on the left of the equality sign is the Left Hand Side (LHS). The expression on the right of the equality sign is the Right Hand Side (RHS).
In an equation the values of the expressions on the LHS and RHS are equal. This happens to be true only for certain values of the variable. These values are the solutions of the equation.
Complete step by step solution:
Given an algebraic equation is $3\left( {4 - 8b} \right) - 3\left( {4b + 6} \right) = - 6$.
We have to find the value of $b$.
First, we have to apply the distributive property in the given equation, i.e., multiplying each addend individually by the number and then adding the products together.
$3 \cdot 4 + 3\left( { - 8b} \right) - 3\left( {4b} \right) - 3 \cdot 6 = - 6$
Calculate the product of each term in the left hand side of the equation.
$ \Rightarrow 12 - 24b - 12b - 18 = - 6$
Add variables terms and constant terms in the left hand side of the equation.
$ \Rightarrow - 36b - 6 = - 6$
Now we have to isolate the variable terms on one side by performing the same mathematical operations on both sides of the equation.
So, adding $6$ to both sides of the equation, we get
$ \Rightarrow - 36b - 6 + 6 = - 6 + 6$
$ \Rightarrow - 36b = 0$
Now we have to make the coefficient of the variable equal to $1$ using multiplication or division property.
So, dividing both sides of the equation by $ - 36$, we get
\[ \Rightarrow \dfrac{{ - 36b}}{{ - 36}} = \dfrac{0}{{ - 36}}\]
$\therefore b = 0$
Final solution: Therefore, $b = 0$ is the solution of $3\left( {4 - 8b} \right) - 3\left( {4b + 6} \right) = - 6$.
Note:
An algebraic equation is an equation involving variables. It has an equality sign. The expression on the left of the equality sign is the Left Hand Side (LHS). The expression on the right of the equality sign is the Right Hand Side (RHS).
In an equation the values of the expressions on the LHS and RHS are equal. This happens to be true only for certain values of the variable. These values are the solutions of the equation.
Recently Updated Pages
Complete reduction of benzene diazonium chloride with class 12 chemistry CBSE

How can you identify optical isomers class 12 chemistry CBSE

The coating formed on the metals such as iron silver class 12 chemistry CBSE

Metals are refined by using different methods Which class 12 chemistry CBSE

What do you understand by denaturation of proteins class 12 chemistry CBSE

Assertion Nitrobenzene is used as a solvent in FriedelCrafts class 12 chemistry CBSE

Trending doubts
Difference Between Plant Cell and Animal Cell

Fill the blanks with the suitable prepositions 1 The class 9 english CBSE

Which places in India experience sunrise first and class 9 social science CBSE

What is pollution? How many types of pollution? Define it

Name 10 Living and Non living things class 9 biology CBSE

What is the full form of pH?

