Solve $15x = 120$
Answer
520.5k+ views
Hint: First of all take the given expression, make the required term the subject by moving all the terms on one side of the equation, find factors of the terms and remove common factors from the numerator and the denominator and simplify for the required value for “x”
Complete step-by-step answer:
Take the given expression: $15x = 120$
Make the required term the subject and move other terms on the opposite side. The term multiplicative on one side if moved to the opposite side then it goes to the denominator.
$x = \dfrac{{120}}{{15}}$
Find factors for the terms in the numerator and the denominator of the above expression –
$x = \dfrac{{3 \times 5 \times 8}}{{3 \times 5}}$
Common multiples in the numerator and the denominator of the above expression cancel each other and therefore remove from the numerator and the denominator.
$ \Rightarrow x = 8$
Hence, this is the required solution.
So, the correct answer is “x = 8”.
Note: Always remember when you move term multiplicative on one side to the opposite side, then it goes to the denominator. We can find factors of the term by long division method, prime factorization or by the factor tree method and remove common factors from the numerator and the denominator when the terms are in the form of the fraction.
Complete step-by-step answer:
Take the given expression: $15x = 120$
Make the required term the subject and move other terms on the opposite side. The term multiplicative on one side if moved to the opposite side then it goes to the denominator.
$x = \dfrac{{120}}{{15}}$
Find factors for the terms in the numerator and the denominator of the above expression –
$x = \dfrac{{3 \times 5 \times 8}}{{3 \times 5}}$
Common multiples in the numerator and the denominator of the above expression cancel each other and therefore remove from the numerator and the denominator.
$ \Rightarrow x = 8$
Hence, this is the required solution.
So, the correct answer is “x = 8”.
Note: Always remember when you move term multiplicative on one side to the opposite side, then it goes to the denominator. We can find factors of the term by long division method, prime factorization or by the factor tree method and remove common factors from the numerator and the denominator when the terms are in the form of the fraction.
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