Question

What is the solution used for the preparation of hydrogen peroxide by electrolytic procedure?
A. $0.2N$$NaOH$
B. $50\% {H_2}S{O_4}$
C. $20\% NaOH$
D. $5\% NaCl$

Answer 1

Hint:We know that the molecular formula of hydrogen peroxide is ${H_2}{O_2}$.Hydrogen peroxide can act like both oxidising agent and reducing agent. When hydrogen peroxide is reduced, we get ${H_2}O$and when hydrogen peroxide is oxidised we obtain ${O_2}$.The molecular mass of hydrogen peroxide is $34$

Complete step by step solution:
We know that hydrogen peroxide can be prepared by the process of electrolysis. Hydrogen peroxide is prepared by the electrolysis of $50\% {H_2}S{O_4}$. For the electrolysis process we take cathode as $Pb$wire and the anode as $Pt$rod. The whole electrolytic reaction can be written as $2HS{O_4}^ - (aq)[electrolysis] \to 2HS{O_4}^ - (aq) + 2{H^ + }(aq) + {H_2}{O_2}(aq)$. We can observe that hydrogen peroxide is obtained in the product side. It is the industrial method of preparation of hydrogen peroxide. So, from the above explanation it is clear to us that the hydrogen peroxide is prepared by the electrolysis of $50\% {H_2}S{O_4}$.

So, the correct answer of the given question is option: B. $50\% {H_2}S{O_4}$

Additional information:
 Hydrogen peroxide is a very important compound. It can be used as an antiseptic. It is used as a bleaching agent in paper and pulp industries. The white blood cell of the human body produces hydrogen peroxide to kill bacteria. It is used in the preservation of milk and wine. Hydrogen peroxide is also known as dihydrogen dioxide. It has a very unstable peroxide bond which is responsible for the reactions of this compound. It is also used to remove blood stains.

Note:
Always remember that the electrolysis of $50\% {H_2}S{O_4}$produces the hydrogen peroxide. It is a very unstable compound. In the electrolysis process, the oxidation reaction occurs at the anode and the reduction occurs in the cathode.