
How do you simplify \[{{\left( -5{{a}^{2}}{{b}^{7}} \right)}^{7}}\]?
Answer
444.3k+ views
Hint: In this problem, we have to simplify the given exponential expression. We know that, since the whole thing is a multiplication, we can distribute the power to each term in the bracket. We can also see that there is a negative, and the power is an odd number therefore, the result should be a negative. We can power the terms individually and combine them, to get the simplified form.
Complete step by step solution:
We know that the given expression to be simplified is,
\[{{\left( -5{{a}^{2}}{{b}^{7}} \right)}^{7}}\]
We know that, since the whole thing is a multiplication, we can distribute the power to each term in the bracket,
\[\Rightarrow \left[ {{\left( - \right)}^{7}}{{\left( 5 \right)}^{7}}{{\left( {{a}^{2}} \right)}^{7}}{{\left( {{b}^{7}} \right)}^{7}} \right]\]
We know that there is a negative, and the power is an odd number therefore, the result should be a negative.
Now we can simplify the above step one by one, we get
\[\Rightarrow \left[ -{{\left( 5 \right)}^{7}}{{\left( a \right)}^{2\times 7}}{{\left( b \right)}^{7\times 7}} \right]\]
We also know that,
\[\Rightarrow {{5}^{7}}=5\times 5\times 5\times 5\times 5\times 5\times 5=3125\]
\[\begin{align}
& \Rightarrow {{\left( a \right)}^{2\times 7}}={{a}^{14}} \\
& \Rightarrow {{\left( b \right)}^{7\times 7}}={{b}^{49}} \\
\end{align}\]
We can now substitute the above values combine these terms in the above step, we get
\[\Rightarrow -3125{{a}^{14}}{{b}^{49}}\]
Therefore, the simplified form of the given expression \[{{\left( -5{{a}^{2}}{{b}^{7}} \right)}^{7}}\] is \[-3125{{a}^{14}}{{b}^{49}}\].
Note: Students make mistakes while multiplying the power terms. We should always remember that the negative sign with odd power plays a significant role, as the negative terms with odd power gives a negative solution and the terms inside the brackets are in multiplication, so we can individually take power for each term. We have to concentrate while multiplying terms with the highest power as it will take time.
Complete step by step solution:
We know that the given expression to be simplified is,
\[{{\left( -5{{a}^{2}}{{b}^{7}} \right)}^{7}}\]
We know that, since the whole thing is a multiplication, we can distribute the power to each term in the bracket,
\[\Rightarrow \left[ {{\left( - \right)}^{7}}{{\left( 5 \right)}^{7}}{{\left( {{a}^{2}} \right)}^{7}}{{\left( {{b}^{7}} \right)}^{7}} \right]\]
We know that there is a negative, and the power is an odd number therefore, the result should be a negative.
Now we can simplify the above step one by one, we get
\[\Rightarrow \left[ -{{\left( 5 \right)}^{7}}{{\left( a \right)}^{2\times 7}}{{\left( b \right)}^{7\times 7}} \right]\]
We also know that,
\[\Rightarrow {{5}^{7}}=5\times 5\times 5\times 5\times 5\times 5\times 5=3125\]
\[\begin{align}
& \Rightarrow {{\left( a \right)}^{2\times 7}}={{a}^{14}} \\
& \Rightarrow {{\left( b \right)}^{7\times 7}}={{b}^{49}} \\
\end{align}\]
We can now substitute the above values combine these terms in the above step, we get
\[\Rightarrow -3125{{a}^{14}}{{b}^{49}}\]
Therefore, the simplified form of the given expression \[{{\left( -5{{a}^{2}}{{b}^{7}} \right)}^{7}}\] is \[-3125{{a}^{14}}{{b}^{49}}\].
Note: Students make mistakes while multiplying the power terms. We should always remember that the negative sign with odd power plays a significant role, as the negative terms with odd power gives a negative solution and the terms inside the brackets are in multiplication, so we can individually take power for each term. We have to concentrate while multiplying terms with the highest power as it will take time.
Recently Updated Pages
The correct geometry and hybridization for XeF4 are class 11 chemistry CBSE

Water softening by Clarks process uses ACalcium bicarbonate class 11 chemistry CBSE

With reference to graphite and diamond which of the class 11 chemistry CBSE

A certain household has consumed 250 units of energy class 11 physics CBSE

The lightest metal known is A beryllium B lithium C class 11 chemistry CBSE

What is the formula mass of the iodine molecule class 11 chemistry CBSE

Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE

Given that HCF 306 657 9 find the LCM 306 657 class 9 maths CBSE

The highest mountain peak in India is A Kanchenjunga class 9 social science CBSE

A piece of wire 20 cm long is bent into the form of class 9 maths CBSE

Difference Between Plant Cell and Animal Cell

What is the difference between Atleast and Atmost in class 9 maths CBSE
