
Show that the dispersion of a grating is ${\text{D}} = (\tan \theta )/\lambda $.
Answer
494.1k+ views
Hint:Dispersion is a phenomena in optics where the phase velocity of a wave is affected by its frequency. Dispersive media are those that have this trait in common.For specificity, the phrase chromatic dispersion is also employed. A rainbow is arguably the most well-known illustration of dispersion.
Complete answer:
The amount of variation in diffraction angle per unit change in wavelength is known as angular dispersion. It's a measurement of the angular spacing between neighbouring wavelengths' beams. Differentiating the grating equation while keeping the angle constant yields a formula for angular dispersion.
Diffraction gratings are used to divide or scatter light into different wavelengths. The relationship between a change in diffraction angle and a slight change in wavelength is known as angular dispersion. Many diffracted orders will be generated by gratings with a low groove frequency. A grating can be used as a beam splitter for monochromatic light, such as from a laser. The maxima (lines) at angles theta come from diffraction by N (multiple) slits,
$d\sin (\theta ) = m\lambda $
where d is the slit-slit spacing.
$D = \dfrac{{d\theta }}{{d\lambda }}$
Differentiate both sides of (1) with respect to theta, and you'll get the dispersion of a grating.
$d\cos (\theta )\dfrac{{d\theta }}{{d\lambda }} = m$
$\Rightarrow \dfrac{{d\theta }}{{d\lambda }} = \dfrac{m}{{d\cos (\theta )}}$
Substituting from $d\sin (\theta ) = m\lambda $ we get,
$\dfrac{{d\theta }}{{d\lambda }} = \dfrac{{d\sin (\theta )}}{{d\cos (\theta )\lambda }}$
$\Rightarrow \dfrac{{d\theta }}{{d\lambda }} = \dfrac{{\tan (\theta )}}{\lambda }$
Hence from the definition of the dispersion we have ${\text{D}} = (\tan \theta )/\lambda $
$ \therefore D = \dfrac{{\tan (\theta )}}{\lambda }$
Hence proved.
Note:Diffraction gratings are commonly employed in spectroscopic equipment to convert white light into monochromatic light. This is accomplished by taking use of the grating's capacity to distribute light of various wavelengths into various angles. The well-known grating equation describes the relationship between the incidence and diffraction angles, as well as the wavelength. Many key spectroscopic parameters, including dispersion, resolution, and free spectral range, may be obtained from the grating equation using very simple algebraic operations.
Complete answer:
The amount of variation in diffraction angle per unit change in wavelength is known as angular dispersion. It's a measurement of the angular spacing between neighbouring wavelengths' beams. Differentiating the grating equation while keeping the angle constant yields a formula for angular dispersion.
Diffraction gratings are used to divide or scatter light into different wavelengths. The relationship between a change in diffraction angle and a slight change in wavelength is known as angular dispersion. Many diffracted orders will be generated by gratings with a low groove frequency. A grating can be used as a beam splitter for monochromatic light, such as from a laser. The maxima (lines) at angles theta come from diffraction by N (multiple) slits,
$d\sin (\theta ) = m\lambda $
where d is the slit-slit spacing.
$D = \dfrac{{d\theta }}{{d\lambda }}$
Differentiate both sides of (1) with respect to theta, and you'll get the dispersion of a grating.
$d\cos (\theta )\dfrac{{d\theta }}{{d\lambda }} = m$
$\Rightarrow \dfrac{{d\theta }}{{d\lambda }} = \dfrac{m}{{d\cos (\theta )}}$
Substituting from $d\sin (\theta ) = m\lambda $ we get,
$\dfrac{{d\theta }}{{d\lambda }} = \dfrac{{d\sin (\theta )}}{{d\cos (\theta )\lambda }}$
$\Rightarrow \dfrac{{d\theta }}{{d\lambda }} = \dfrac{{\tan (\theta )}}{\lambda }$
Hence from the definition of the dispersion we have ${\text{D}} = (\tan \theta )/\lambda $
$ \therefore D = \dfrac{{\tan (\theta )}}{\lambda }$
Hence proved.
Note:Diffraction gratings are commonly employed in spectroscopic equipment to convert white light into monochromatic light. This is accomplished by taking use of the grating's capacity to distribute light of various wavelengths into various angles. The well-known grating equation describes the relationship between the incidence and diffraction angles, as well as the wavelength. Many key spectroscopic parameters, including dispersion, resolution, and free spectral range, may be obtained from the grating equation using very simple algebraic operations.
Recently Updated Pages
A man running at a speed 5 ms is viewed in the side class 12 physics CBSE

The number of solutions in x in 02pi for which sqrt class 12 maths CBSE

State and explain Hardy Weinbergs Principle class 12 biology CBSE

Write any two methods of preparation of phenol Give class 12 chemistry CBSE

Which of the following statements is wrong a Amnion class 12 biology CBSE

Differentiate between action potential and resting class 12 biology CBSE

Trending doubts
What are the major means of transport Explain each class 12 social science CBSE

Which are the Top 10 Largest Countries of the World?

Draw a labelled sketch of the human eye class 12 physics CBSE

How much time does it take to bleed after eating p class 12 biology CBSE

Explain sex determination in humans with line diag class 12 biology CBSE

Explain sex determination in humans with the help of class 12 biology CBSE

