
Select the correct order of acidic strength.
(This question has multiple correct options.)
A) ${ BF }_{ 3 }{ >Me }_{ 3 }{ B }$
B) ${ CH }_{ 3 }{ \equiv C-H}$$ < $${CH }_{ 2 }{ =CH-H>CH }_{ 3 }{ -CH }_{ 2 }{ -H }$
C) ${ BF }_{ 3 }$$ < $${Me }_{ 3 }{ B }$
D) ${ CH }_{ 3 }{ \equiv C-H > CH }_{ 2 }{ =CH-H>CH }_{ 3 }{ -CH }_{ 2 }{ -H }$
Answer
600k+ views
Hint: Acidic strength refers to its ability to lose a proton ${ H }^{ + }$.
Back bonding is an additional pi bond formed between two atoms of which one has an empty orbital and another must-have lone pair.
Complete step-by-step answer:
The order of acidic strength is alkane < alkene < alkyne. and this is because of their hybridization and hence alkanes are the least electronegative whereas, an alkyne is the most electronegative.
${ H-C\equiv HC\rightarrow }{ H-C\equiv C }^{ \_ }$
${ R-CH=CH }_{ 2 }{ \rightarrow R-CH=C^{ \_ }H^{ + } }$
${ H-CH }_{ 2 }{ -CH }_{ 3 }{ \rightarrow H-CH }_{ 2 }{ C }^{ - }{ H }_{ 2 }$
The ${ C }^{ - }$ is sp hybridized, so it can hold negative.
The carbon with a triple bond is more electronegative and hence, can hold a negative charge and is most stable. Hence, an alkyne is more stable than alkene and alkene is more than alkane.
So, the correct order of acidic strength will be
${ CH }_{ 3 }{ \equiv C-H>CH }_{ 2 }{ =CH-H>CH }_{ 3 }{ -CH }_{ 2 }{ -H }$
Now, among boron trihalides, maximum ${ p\Pi -p\Pi }$, back bonding exists in ${ BF }_{ 3 }$. This is because as the size of the halogen atom increases down the group, the overlapping of the vacant ${ 2p }$ orbital of boron cannot take place easily and efficiently with the p-orbitals of high energy levels. While there is an absence of π-back bonding in ${ Me }_{ 3 }{ B }$.
As we know that back bonding is inversely proportional to acidic strength, so ${ Me }_{ 3 }{ B }$ will be more acidic than ${ BF }_{ 3 }$.
Hence, the correct options are C and D.
Note: The possibility to make a mistake is that you may choose option A. But ${BF}_{3 }$$<$${Me }_{ 3 }{ B }$ is more acidic as there is a pi back bonding present in ${BF}_{3}$ molecule which will increase the stability.
Back bonding is an additional pi bond formed between two atoms of which one has an empty orbital and another must-have lone pair.
Complete step-by-step answer:
The order of acidic strength is alkane < alkene < alkyne. and this is because of their hybridization and hence alkanes are the least electronegative whereas, an alkyne is the most electronegative.
${ H-C\equiv HC\rightarrow }{ H-C\equiv C }^{ \_ }$
${ R-CH=CH }_{ 2 }{ \rightarrow R-CH=C^{ \_ }H^{ + } }$
${ H-CH }_{ 2 }{ -CH }_{ 3 }{ \rightarrow H-CH }_{ 2 }{ C }^{ - }{ H }_{ 2 }$
The ${ C }^{ - }$ is sp hybridized, so it can hold negative.
The carbon with a triple bond is more electronegative and hence, can hold a negative charge and is most stable. Hence, an alkyne is more stable than alkene and alkene is more than alkane.
So, the correct order of acidic strength will be
${ CH }_{ 3 }{ \equiv C-H>CH }_{ 2 }{ =CH-H>CH }_{ 3 }{ -CH }_{ 2 }{ -H }$
Now, among boron trihalides, maximum ${ p\Pi -p\Pi }$, back bonding exists in ${ BF }_{ 3 }$. This is because as the size of the halogen atom increases down the group, the overlapping of the vacant ${ 2p }$ orbital of boron cannot take place easily and efficiently with the p-orbitals of high energy levels. While there is an absence of π-back bonding in ${ Me }_{ 3 }{ B }$.
As we know that back bonding is inversely proportional to acidic strength, so ${ Me }_{ 3 }{ B }$ will be more acidic than ${ BF }_{ 3 }$.
Hence, the correct options are C and D.
Note: The possibility to make a mistake is that you may choose option A. But ${BF}_{3 }$$<$${Me }_{ 3 }{ B }$ is more acidic as there is a pi back bonding present in ${BF}_{3}$ molecule which will increase the stability.
Recently Updated Pages
Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Business Studies: Engaging Questions & Answers for Success

Trending doubts
Which are the Top 10 Largest Countries of the World?

What are the major means of transport Explain each class 12 social science CBSE

Draw a labelled sketch of the human eye class 12 physics CBSE

Why cannot DNA pass through cell membranes class 12 biology CBSE

Differentiate between insitu conservation and exsitu class 12 biology CBSE

Draw a neat and well labeled diagram of TS of ovary class 12 biology CBSE

