Answer
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Hint: In this particular type of question use the concept that square of a number (say xy) according to Sutra Ekadhikena Purvena method is the square of the last digit and the first digit is multiplied by the next digit (i.e. x + 1) and it is written in the form which is given as${\left( {xy} \right)^2} = \left( {x + 1} \right){y^2}$, where (x+1) is not multiplied by square of y it is written just like that.
Complete step-by-step answer:
Now,
Sutra Ekadhikena Purvena method does not give all the squares it is satisfied for some of the particular squares which end with 5.
Let’s verify this,
So, let us have to find the square of 12.
So according to Sutra Ekadhikena Purvena method the square of a number is written as,
The square of the last digit and the first digit is multiplied by the next digit (i.e. x + 1) and it is written in the form which is given as${\left( {xy} \right)^2} = \left( {x + 1} \right){y^2}$, where (x+1) is not multiplied by square of y it is written just like that.
So the square of 12 according to this method is
${\left( {12} \right)^2} = \left( {1 \times 2} \right){2^2} = 24$
So as we know that 12 squares is 144 but according to Sutra Ekadhikena Purvena method it comes out to 24 which is not right.
Now let’s take an example ending with 5.
So consider 15, so the square of 15 according to this method is,
${\left( {15} \right)^2} = \left( {1 \times 2} \right){5^2} = 225$
So as we know that the square of 15 is 225 which is the same as above calculated.
Let’s take another example ending with 5.
So consider 25, so the square of 25 according to this method is,
${\left( {25} \right)^2} = \left( {2 \times 3} \right){5^2} = 625$
So as we know that the square of 25 is 625 which is the same as above calculated.
So overall we can say that to find the square of a number by the Sutra Ekadhikena Purvena method, the number should end with 5.
So the given statement is true.
Note – Whenever we face such types of questions always recall the Sutra Ekadhikena Purvena method to find the square of a number which is stated above so consider the examples as above taken and find the squares as above we will get that to find square of number by Sutra Ekadhikena Purvena method, the number should end with 5.
Complete step-by-step answer:
Now,
Sutra Ekadhikena Purvena method does not give all the squares it is satisfied for some of the particular squares which end with 5.
Let’s verify this,
So, let us have to find the square of 12.
So according to Sutra Ekadhikena Purvena method the square of a number is written as,
The square of the last digit and the first digit is multiplied by the next digit (i.e. x + 1) and it is written in the form which is given as${\left( {xy} \right)^2} = \left( {x + 1} \right){y^2}$, where (x+1) is not multiplied by square of y it is written just like that.
So the square of 12 according to this method is
${\left( {12} \right)^2} = \left( {1 \times 2} \right){2^2} = 24$
So as we know that 12 squares is 144 but according to Sutra Ekadhikena Purvena method it comes out to 24 which is not right.
Now let’s take an example ending with 5.
So consider 15, so the square of 15 according to this method is,
${\left( {15} \right)^2} = \left( {1 \times 2} \right){5^2} = 225$
So as we know that the square of 15 is 225 which is the same as above calculated.
Let’s take another example ending with 5.
So consider 25, so the square of 25 according to this method is,
${\left( {25} \right)^2} = \left( {2 \times 3} \right){5^2} = 625$
So as we know that the square of 25 is 625 which is the same as above calculated.
So overall we can say that to find the square of a number by the Sutra Ekadhikena Purvena method, the number should end with 5.
So the given statement is true.
Note – Whenever we face such types of questions always recall the Sutra Ekadhikena Purvena method to find the square of a number which is stated above so consider the examples as above taken and find the squares as above we will get that to find square of number by Sutra Ekadhikena Purvena method, the number should end with 5.
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