
What can you say about the prime factorization of the denominator of $27.\overline{142857}$?
Answer
481.8k+ views
Hint: We have a repeating decimal number. We will first convert this number into a fraction. There are ways to convert different types of decimal numbers into fractions. We will be using the process that involves converting repeating decimals into fractions. Then we will look at the prime factorization of the denominator.
Complete step by step answer:
To convert the given repeating decimal number, we will write the given number in the following manner, $27.\overline{142857}=27+0.\overline{142857}$.
So, the numerator of the fraction will have the number 142857. Since all the six digits after the decimal are repeating, the denominator of the fraction will have six 9's. As there are no non-repeating digits after the decimal, the 9's in the denominator will not be followed by any zeros.
So, we have $0.\overline{142857}=\dfrac{142857}{999999}$.
Therefore, the given decimal number will be converted into fraction as follows,
$27.\overline{142857}=27+0.\overline{142857}$
We will substitute the fraction value of the repeating decimal. So, we now have the following,
$27.\overline{142857}=27+\dfrac{142857}{999999}$
Taking the LCM of the above expression, we get
$27.\overline{142857}=\dfrac{26999973+142857}{999999}$
Simplifying this expression, we have
$27.\overline{142857}=\dfrac{27142830}{999999}$
Next, we have to look at the prime factorization of the denominator. The denominator is 999999. This number can be factorized by prime numbers as follows,
$999999=3\times 3\times 3\times 7\times 11\times 13\times 37$.
Note: It is crucial to follow the correct method while converting a decimal number into a fraction. The calculations involve large numbers. Therefore, it is useful to write the calculations explicitly so that minor mistakes can be avoided. While factoring any number into its prime factors, it is useful to know the divisibility tests.
Complete step by step answer:
To convert the given repeating decimal number, we will write the given number in the following manner, $27.\overline{142857}=27+0.\overline{142857}$.
So, the numerator of the fraction will have the number 142857. Since all the six digits after the decimal are repeating, the denominator of the fraction will have six 9's. As there are no non-repeating digits after the decimal, the 9's in the denominator will not be followed by any zeros.
So, we have $0.\overline{142857}=\dfrac{142857}{999999}$.
Therefore, the given decimal number will be converted into fraction as follows,
$27.\overline{142857}=27+0.\overline{142857}$
We will substitute the fraction value of the repeating decimal. So, we now have the following,
$27.\overline{142857}=27+\dfrac{142857}{999999}$
Taking the LCM of the above expression, we get
$27.\overline{142857}=\dfrac{26999973+142857}{999999}$
Simplifying this expression, we have
$27.\overline{142857}=\dfrac{27142830}{999999}$
Next, we have to look at the prime factorization of the denominator. The denominator is 999999. This number can be factorized by prime numbers as follows,
$999999=3\times 3\times 3\times 7\times 11\times 13\times 37$.
Note: It is crucial to follow the correct method while converting a decimal number into a fraction. The calculations involve large numbers. Therefore, it is useful to write the calculations explicitly so that minor mistakes can be avoided. While factoring any number into its prime factors, it is useful to know the divisibility tests.
Recently Updated Pages
The correct geometry and hybridization for XeF4 are class 11 chemistry CBSE

Water softening by Clarks process uses ACalcium bicarbonate class 11 chemistry CBSE

With reference to graphite and diamond which of the class 11 chemistry CBSE

A certain household has consumed 250 units of energy class 11 physics CBSE

The lightest metal known is A beryllium B lithium C class 11 chemistry CBSE

What is the formula mass of the iodine molecule class 11 chemistry CBSE

Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE

Given that HCF 306 657 9 find the LCM 306 657 class 9 maths CBSE

The highest mountain peak in India is A Kanchenjunga class 9 social science CBSE

A piece of wire 20 cm long is bent into the form of class 9 maths CBSE

Difference Between Plant Cell and Animal Cell

What is the difference between Atleast and Atmost in class 9 maths CBSE
