Question

Salil wants to put a picture in a frame. The picture is ${\text{7}}\dfrac{3}{5}cm$ wide. To fit in the frame the picture cannot be more than ${\text{7}}\dfrac{3}{{10}}cm$ wide. How much should the picture be trimmed?

Answer 1

Hint- Picture should be trimmed by$ = $width of the picture$ - $width of the frame.
The width of the picture is ${\text{7}}\dfrac{3}{5}cm$
This is in mixed fraction format convert it into improper fraction${\text{ = 7}}\dfrac{3}{5}cm = \dfrac{{38}}{5}cm = \dfrac{{76}}{{10}}cm$
Because whenever the numerator is greater than the denominator fraction is called improper fraction otherwise called proper fraction.
And the width of the frame is ${\text{7}}\dfrac{3}{{10}}cm$
This is also in mixed fraction format convert it into improper fraction${\text{ = 7}}\dfrac{3}{{10}}cm = \dfrac{{73}}{{10}}cm$
Because whenever the numerator is greater than the denominator fraction is called improper fraction otherwise called proper fraction.
Clearly the width of the picture is greater than the width of the frame.
$ \Rightarrow $Picture should be trimmed to get fit into the frame.
$ \Rightarrow $Picture should be trimmed by$ = $width of the picture$ - $width of the frame
$\begin{gathered}
   \Rightarrow {\text{7}}\dfrac{3}{5}cm - {\text{ 7}}\dfrac{3}{{10}}cm \\
   \Rightarrow \dfrac{{38}}{5} - \dfrac{{73}}{{10}} = \dfrac{{76}}{{10}} - \dfrac{{73}}{{10}} = \dfrac{3}{{10}}cm \\
\end{gathered} $
Therefore picture should be trimmed by $\dfrac{3}{{10}}cm.$
So, this is the required answer.

Note- In such types of questions first convert the mixed fraction into improper fraction (Because whenever the numerator is greater than the denominator fraction is called improper fraction otherwise called proper fraction.) and check whether the width of the picture is greater than width of the frame if yes then subtract width of the frame from the width of the picture, we will get the required trimmed portion.