
Rs 6500 were divided equally among a certain number of persons. Had there been 15 more persons, each would have got Rs 30 less. Find the original number of persons.
Answer
609k+ views
Hint: Find the share of each individual before and after decreasing the share by adding 15 persons. Use it with the given information and factorize to get the final answer.
Complete step-by-step answer:
Total amount of money = Rs 6500
Let the original number of people be x
Then the share of an individual would be $\dfrac{{6500}}{x}$
After adding 15 people , total number of people = x + 15
Share of an individual after increasing 15 people = $\dfrac{{6500}}{{x + 15}}$
But it is given that when 15 people were added each individual gets Rs 30 less
Therefore ,
$\dfrac{{6500}}{x} - \dfrac{{6500}}{{x + 15}} = 30$ ( subtracting both the equations )
$ \Rightarrow 6500\left( {\dfrac{{x + 16 - x}}{{x\left( {x + 15} \right)}}} \right) = 30$
$ \Rightarrow 650\left( {15} \right) = 3\left( {{x^2} + 15x} \right)$
$ \Rightarrow {x^2} + 15x - 3250 = 0$
$ \Rightarrow {x^2} + 65x - 50x - 3250 = 0$ (factorizing)
$ \Rightarrow x\left( {x + 65} \right) - 50\left( {x + 65} \right)$
$\left( {x + 65} \right)\left( {x - 50} \right) = 0$
Taking positive value of x , we get x = 50
Therefore,
Initial number of people were 50.
Note: The negative value that comes after factorization should be ignored in such problems. Simplification while solving lengthy equations saves time and decreases the chances of errors.
Complete step-by-step answer:
Total amount of money = Rs 6500
Let the original number of people be x
Then the share of an individual would be $\dfrac{{6500}}{x}$
After adding 15 people , total number of people = x + 15
Share of an individual after increasing 15 people = $\dfrac{{6500}}{{x + 15}}$
But it is given that when 15 people were added each individual gets Rs 30 less
Therefore ,
$\dfrac{{6500}}{x} - \dfrac{{6500}}{{x + 15}} = 30$ ( subtracting both the equations )
$ \Rightarrow 6500\left( {\dfrac{{x + 16 - x}}{{x\left( {x + 15} \right)}}} \right) = 30$
$ \Rightarrow 650\left( {15} \right) = 3\left( {{x^2} + 15x} \right)$
$ \Rightarrow {x^2} + 15x - 3250 = 0$
$ \Rightarrow {x^2} + 65x - 50x - 3250 = 0$ (factorizing)
$ \Rightarrow x\left( {x + 65} \right) - 50\left( {x + 65} \right)$
$\left( {x + 65} \right)\left( {x - 50} \right) = 0$
Taking positive value of x , we get x = 50
Therefore,
Initial number of people were 50.
Note: The negative value that comes after factorization should be ignored in such problems. Simplification while solving lengthy equations saves time and decreases the chances of errors.
Recently Updated Pages
You are awaiting your class 10th results Meanwhile class 7 english CBSE

Questions & Answers - Ask your doubts

A man running at a speed 5 ms is viewed in the side class 12 physics CBSE

State and explain Hardy Weinbergs Principle class 12 biology CBSE

Which of the following statements is wrong a Amnion class 12 biology CBSE

Two Planoconcave lenses 1 and 2 of glass of refractive class 12 physics CBSE

Trending doubts
Convert 200 Million dollars in rupees class 7 maths CBSE

Full Form of IASDMIPSIFSIRSPOLICE class 7 social science CBSE

What are the controls affecting the climate of Ind class 7 social science CBSE

Write a letter to the editor of the national daily class 7 english CBSE

Welcome speech for Christmas day celebration class 7 english CBSE

List of coprime numbers from 1 to 100 class 7 maths CBSE


