# Roy is 11 years old and his uncle is 59 years old. How many years ago was Roy’s uncle 7 times as old as Roy?

Last updated date: 18th Mar 2023

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Answer

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Hint: We have to observe the relationship between the ages of Roy and his uncle to solve this problem.

Complete step-by-step answer:

Let the present age of Roy be r = 11 years

And the present age of Roy’s uncle be u = 59 years

From the given information, a few years ago Roy’s uncle was 7 times the age of Roy.

Let those few years = y years.

So ‘y’ years ago Roy age = (11 – y) years and his uncle age = (59 – y) years

$ \Rightarrow 59 - y = 7(11 - y)$

$\eqalign{

& \Rightarrow 6y = 18 \cr

& \Rightarrow y = \dfrac{{18}}{6} \cr} $

$ \Rightarrow y = 3$

$\therefore $ 3 years ago Roy’s uncle was 7 times as old as Roy.

Note: We have to convert the given information into algebraic equations. We need to observe their present ages and their ages before a few years go accordingly. Then we can easily solve the equation to get the required result.

Complete step-by-step answer:

Let the present age of Roy be r = 11 years

And the present age of Roy’s uncle be u = 59 years

From the given information, a few years ago Roy’s uncle was 7 times the age of Roy.

Let those few years = y years.

So ‘y’ years ago Roy age = (11 – y) years and his uncle age = (59 – y) years

$ \Rightarrow 59 - y = 7(11 - y)$

$\eqalign{

& \Rightarrow 6y = 18 \cr

& \Rightarrow y = \dfrac{{18}}{6} \cr} $

$ \Rightarrow y = 3$

$\therefore $ 3 years ago Roy’s uncle was 7 times as old as Roy.

Note: We have to convert the given information into algebraic equations. We need to observe their present ages and their ages before a few years go accordingly. Then we can easily solve the equation to get the required result.

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