When red-flowered plants are crossed with white-flowered plants, the \[{{F}_{2}}\] generation gives a ratio of $3:1$. What do you conclude?
A. That there is a lethal gene
B. That there is independent assortment
C. That white colour is dominant
D. That red colour is dominant
Answer
581.7k+ views
Hint: In the given cross, red-coloured flowers were seen in more numbers in \[{{F}_{2}}\] generation. This means that allele for red colour if present alone, shows its expression. The white colour expression needs a homologous pairing of alleles for white colour.
Complete answer: The given cross is carried out between one red-coloured flowering plant and one white coloured flowering plant. It means that the red-coloured flowering plant will have a genotype of RR and the white-coloured flowering plant will have genotype rr. R and r are two different alleles determining the red and white colour in flowers respectively.
Now, when these pure parents were crossed they produced \[{{F}_{1}}\] generation. The \[{{F}_{1}}\] generation was then self-crossed to produce \[{{F}_{2}}\] generation. The \[{{F}_{2}}\] generation came out of having three red-coloured flowering plants and one white coloured flowering plant. This shows that the red colour is dominant over the white colour. Even a single allele of red colour along with white colour is able to express itself completely. If co-dominance would have occurred then \[{{F}_{2}}\] generation would be showing 1 red, 2 pink, and 1 white-flowered plant. But this did not happen. The above conclusion can be confirmed by a test cross. A test cross is performed between the dominant progeny and its recessive parent. All of the progeny in \[{{F}_{1}}\] will have red-coloured flowers as red is dominant. The genotype of \[{{F}_{1}}\] generation will be Rr if the conclusion is true. The test cross will result in half red and half white flowers which ensures that the \[{{F}_{1}}\] generation will have a heterozygous dominant character.
So, the correct answer is option D.
Note: A test cross is used to check the zygosity of an organism. If an organism is heterozygous dominant, then it will always produce half dominant and half recessive progenies when crossed with its double recessive parent. Thus, the dominance of a trait can be found out with this method.
Complete answer: The given cross is carried out between one red-coloured flowering plant and one white coloured flowering plant. It means that the red-coloured flowering plant will have a genotype of RR and the white-coloured flowering plant will have genotype rr. R and r are two different alleles determining the red and white colour in flowers respectively.
Now, when these pure parents were crossed they produced \[{{F}_{1}}\] generation. The \[{{F}_{1}}\] generation was then self-crossed to produce \[{{F}_{2}}\] generation. The \[{{F}_{2}}\] generation came out of having three red-coloured flowering plants and one white coloured flowering plant. This shows that the red colour is dominant over the white colour. Even a single allele of red colour along with white colour is able to express itself completely. If co-dominance would have occurred then \[{{F}_{2}}\] generation would be showing 1 red, 2 pink, and 1 white-flowered plant. But this did not happen. The above conclusion can be confirmed by a test cross. A test cross is performed between the dominant progeny and its recessive parent. All of the progeny in \[{{F}_{1}}\] will have red-coloured flowers as red is dominant. The genotype of \[{{F}_{1}}\] generation will be Rr if the conclusion is true. The test cross will result in half red and half white flowers which ensures that the \[{{F}_{1}}\] generation will have a heterozygous dominant character.
So, the correct answer is option D.
Note: A test cross is used to check the zygosity of an organism. If an organism is heterozygous dominant, then it will always produce half dominant and half recessive progenies when crossed with its double recessive parent. Thus, the dominance of a trait can be found out with this method.
Recently Updated Pages
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Trending doubts
Which are the Top 10 Largest Countries of the World?

Draw a labelled sketch of the human eye class 12 physics CBSE

Explain the structure of megasporangium class 12 biology CBSE

What are the major means of transport Explain each class 12 social science CBSE

Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE

Sulphuric acid is known as the king of acids State class 12 chemistry CBSE

