
What is the ratio of molecules in 1 mole of $N{H_3}$ and 1 mole of $HN{O_3}$?
Answer
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Hint: In order to answer the question, first we have to find the number of molecules in 1 mole of both the compounds. Then to find the ratio between both the compounds with their number of molecules, by dividing them.
Complete step by step solution:
We all know that, according to Mole Concept, Mole is a S.I unit which is used to measure the amount of the chemical compounds. And the definition of Mole says, a constant amount of molecules are present in 1 mole amount of any chemical compound which is the Avagadro’s number that is $6.023 \times {10^{23}}$ .
1 mole of any compound is the Avogadro’s number, $6.023 \times {10^{23}}$ .
$1 \,mole\, of \, N{H_3} $= $6.023 \times {10^{23}}$ molecules
And, 1 mole of $HN{O_3}$ = $6.023 \times {10^{23}}$ molecules.
Now, both compounds have the same number of molecules.
So, by dividing both the above calculation,
$\dfrac{{1\, mole \,of \,N{H_3}}}{{1\, mole \,of \, HN{O_3}}} = \dfrac{{6.023 \times {{10}^{23}}}}{{6.023 \times {{10}^{23}}}}$ $ = \dfrac{1}{1}$,
The ratio of molecules between both the compounds is $1:1$ .
Additional Information:
After solving this question, a question can be raised in a student's mind: why do we measure any atoms in the term of mole and what happens when one mole of any atom will react with the same mole of other atoms? So, mole is nothing but it is the replacement of a very large number for our sake of convenience, mole is the approx. measurement of any atoms. And when we will react to one mole of any atoms with the same one mole of other atoms then it again gives one mole of other atoms.
Note: $N{H_3}$ is a weak base whereas $HN{O_3}$ is a strong acid. Ammonia is a compound of nitrogen and hydrogen, whose molecular formula is $N{H_3}$. Ammonia is used in its gaseous form and the nitric acid is concentrated. The reaction is violent owing to its highly exothermic nature.
Complete step by step solution:
We all know that, according to Mole Concept, Mole is a S.I unit which is used to measure the amount of the chemical compounds. And the definition of Mole says, a constant amount of molecules are present in 1 mole amount of any chemical compound which is the Avagadro’s number that is $6.023 \times {10^{23}}$ .
1 mole of any compound is the Avogadro’s number, $6.023 \times {10^{23}}$ .
$1 \,mole\, of \, N{H_3} $= $6.023 \times {10^{23}}$ molecules
And, 1 mole of $HN{O_3}$ = $6.023 \times {10^{23}}$ molecules.
Now, both compounds have the same number of molecules.
So, by dividing both the above calculation,
$\dfrac{{1\, mole \,of \,N{H_3}}}{{1\, mole \,of \, HN{O_3}}} = \dfrac{{6.023 \times {{10}^{23}}}}{{6.023 \times {{10}^{23}}}}$ $ = \dfrac{1}{1}$,
The ratio of molecules between both the compounds is $1:1$ .
Additional Information:
After solving this question, a question can be raised in a student's mind: why do we measure any atoms in the term of mole and what happens when one mole of any atom will react with the same mole of other atoms? So, mole is nothing but it is the replacement of a very large number for our sake of convenience, mole is the approx. measurement of any atoms. And when we will react to one mole of any atoms with the same one mole of other atoms then it again gives one mole of other atoms.
Note: $N{H_3}$ is a weak base whereas $HN{O_3}$ is a strong acid. Ammonia is a compound of nitrogen and hydrogen, whose molecular formula is $N{H_3}$. Ammonia is used in its gaseous form and the nitric acid is concentrated. The reaction is violent owing to its highly exothermic nature.
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